Quantitative Aptitude - Arithmetic Ability Questions

$$\begin{gathered} 10+25+108+154+225 \\ 10+25+108+154+15 \\ 10+25+108+13 \\ 10+25+11 \\ 10+6 \\ 16 \\ =4 \end{gathered}$$

A=S2

The first train covers 180 kms in 5 hrs

=> Speed = 180/5 = 36 kmph

Now the second train covers the same distance in 1 hour less than the first train => 4 hrs

=> Speed of the second train = 180/4 = 45 kmph

Now, required difference in distance in 1 hour = 45 - 36 = 9 kms.

Speed on return trip = 150% of 50 = 75 km/hr.

Average speed = (2 x 50 x 75)/(50 + 75) = 60 km/hr.

By trial and error method from the given options,

as 54 - 45 =  (1/11) x (45+54)  = 99/11  = 9

Hence this satisfies the given conditions.

Then the woman's husband age is 54.

Let the Number be x. 

Given that one third of a Number is 96. 

i.e x = 3 x 96 = 288.

 67% of  x = x×67100=288×67100=192.96

Here in 100P2, P says that permutations and is defined as in how many ways 2 objects can be selected from 100 and can be arranged.

That can be done as,

100 P2 = 100!/(100 - 2)!

= 100 x 99 x 98!/98!

= 100 x 99 

= 9900.