6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Along a yard 225 metres long, 26 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between two consecutive trees

A) 8	B) 9
C) 10	D) 11

Answer & Explanation Answer: B) 9

Explanation:

26 trees have 25 gaps between them,
Required distance (225/25) = 9

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Filed Under: Simplification

6 8080

Q:

For how many integer values of n will the value of the expression 4n + 7 be an integer greater than 1 and less than 200?

A) 48	B) 49
C) 50	D) 51

Answer & Explanation Answer: C) 50

Explanation:

1 < 4n + 7 < 200

n can be 0, or -1

n cannot be -2 or any other negative integer or the expression 4n + 7 will be less than1.

The largest value for n will be an integer < (200 - 7) /4

193/4 = 48.25, hence 48

The number of integers between -1 and 48 inclusive is 50

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Filed Under: Numbers
Exam Prep: GRE

2 8068

Q:

If 6 engines consume 24 metric tonnes of coal, when each is working 8 hours day, how much coal will be required for 9 engines, each running 13hours a day, it being given that 2 engines of former type consume as much as 3 engines of latter type ?

A) 45 metric tonnes	B) 47 metric tonnes
C) 55 metric tonnes	D) 34 metric tonnes

Answer & Explanation Answer: A) 45 metric tonnes

Explanation:

2 engines of former type for one hour consumes (2 x 24)/(6 x8) = 1 metric ton

i.e. 3 engines of latter type consumes 1 ton for one hour

Hence 9 engines consumes 3 tons for one hour

For 15 hours it is 15 x 3 = 45 metric tonnes.

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Filed Under: Time and Work
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

3 8068

Q:

6 pumps of kirlosker can fill a tank in 7 days and 2 similar pumps of USHA can fill the same tank in 18 days. what is the ratio of the efficiency of a kirlosker pump and a USHA pump?

A) 6:7	B) 7:6
C) 7:54	D) None of these

Answer & Explanation Answer: A) 6:7

Explanation:

The number of days required by a single kirlosker pump to fill the tank = 6 x 7 =42 days and the number of days required by a single USHA pump to fill the same tank = 2 x 18 =36 days.

Now , since efficiency is inversely proportional to the number of days. Hence,

$\frac{E f f i c i e n c y o f o n e K - p u m p}{E f f i c i e n c y o f U - p u m p} = \frac{36}{42} = \frac{6}{7}$

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Filed Under: Ratios and Proportions

7 8065

Q:

One third of a Number is 96. What will 67% of that Number be?

A) 192.96	B) 181.44
C) 169.92	D) 204.48

Answer & Explanation Answer: A) 192.96

Explanation:

Let the Number be x.

Given that one third of a Number is 96.

i.e x = 3 x 96 = 288.

67% of x = $\frac{x \times 67}{100} = \frac{288 \times 67}{100} = 192.96$

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams
Job Role: Bank PO

3 8054

Q:

The respective ratio between the speed of a bike, a van and lorry is 3 : 5 : 2. The speed of the van is 250 percent of the speed of the lorry which covers 360 km in 12 hours. What is the average speed of the bike and the van together?

A) 60 kmph	B) 62 kmph
C) 64 kmph	D) 63 kmph

Answer & Explanation Answer: A) 60 kmph

Explanation:

Speed of lorry = $\frac{360}{12}$ = 30 kmph

Speed of van = $\frac{250}{100} x 30$ = 75 kmph

Speed of bike = $\frac{3}{5} x 75$ = 45 kmph

Therefore, now required average speed of bike and van = $\frac{75 + 45}{2}$ = 60 kmph.

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Filed Under: Time and Distance
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

12 8050

Q:

The bankers discount and the true discount of a sum at 10% per annum simple interest for the same time are Rs.100 and Rs.80 respectively. What is the sum and the time?

A) Sum = Rs.400 and Time = 5 years	B) Sum = Rs.200 and Time = 2.5 years
C) Sum = Rs.400 and Time = 2.5 years	D) Sum = Rs.200 and Time = 5 years

Answer & Explanation Answer: C) Sum = Rs.400 and Time = 2.5 years

Explanation:

BD = Rs.100

TD = Rs.80

R = 10%

$F = \frac{B D \times T D}{B D - T D} = \frac{100 \times 80}{100 - 80} = R s . 400$

BD = Simple interest on the face value of the bill for unexpired time= FTR/100

$\Rightarrow 100 = \frac{400 \times T \times 10}{100}$

=> T = 2.5 years

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Filed Under: Banker's Discount

4 8044

Q:

K and L start the business, with L investing the total capital of Rs. 40,000 on the condition that K pays L interest @ 8% per annum on his half of the capital. L is a working partner and receives Rs.1200 per month from the total profit and any profit reamaining is equally shared by both of them. At the end of the year, it was found that the income of L is twice that of K. Find the total profit for the year ?

A) Rs.44000	B) Rs.46400
C) Rs.480800	D) Rs.46000

Answer & Explanation Answer: B) Rs.46400

Explanation:

Interest received by L from K = 8% of half of Rs.40,000

$\Rightarrow \frac{8}{100} \times 20000 = 1600$

Amount received by L per annum for being a working partner = 1200 x 12 = Rs.14,400

Quantitative Aptitude - Arithmetic Ability Questions

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