Quantitative Aptitude - Arithmetic Ability Questions

BD = Rs.100

TD = Rs.80

R = 10%

F=BD×TDBD-TD=100×80100-80=Rs.400 

BD = Simple interest on the face value of the bill for unexpired time= FTR/100

$$\begin{gathered} ⇒100=400×T×10100 \\ \end{gathered}$$

=> T = 2.5 years

Let the Oranges be 'O', Bananas be 'B' and Apples be 'A'

From the given data,

2O + 3B + 4A = 15 ...... (I)

3O + 2B + A = 10 ..... (II)

On adding (I) and (II),

5O + 5B + 5A = 25

O + B + A = 5

4O + 4B + 4A = 20.

Given total applicants = 135
Given graduates are G=60
Otherthan graduates=135-60 = 75
Given experienced candidates = 80
1) For maximum number of graduates have experience
    Total graduates to have experience = 60

2) For minimum number of graduates have experience
    Remaining after taking other than graduates in experience= 80-75 = 5

26 trees have 25 gaps between them,
Required distance (225/25) = 9

Here given soldier shots 7 shots in 12 min

=> 1 shot doen't take any time in 12 min 

=> Only 6 shots take 12 min 

12 min ------ 6 shots 

90 min ------ ? shots 

=> 90 x (6/12) = 45 

Therefore, total shots fired in 90 minutes = 45 + 1 = 46 shots.

Let the initial amount of honey in the jar was k, then

 512 = k1 - 154 or 512 = k454 

 => k = 512 × 625256 

=> k = 1250

 Hence initially the honey in the jar = 1.25 kg

Let the ten's digit be x and unit's digit be y. Then, (10x + y) - (x + y) = 9 or x = 1.

From this data we cannot find  y, the unit's digit. So the data is inadequate..

100
65
-------
65 ------- 35
100 ------ ? => 53.84 %