6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A train 900 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 min, then the length of the tunnel is ?

A) 400 m	B) 300 m
C) 500 m	D) 600 m

Answer & Explanation Answer: A) 400 m

Explanation:

Speed = 78 x 5/18 = 65/3 m/sec.
Time = 1 min = 60 sec.
Let the length of the train be x meters.
Then, (900 + x)/60 = 65/3
x = 400 m.

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Filed Under: Problems on Trains
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7 7998

Q:

The average marks of a student in 7 subjects is 85. His average marks in 6 subjects except English is 83. What is his marks in English ?

A) 97	B) 98
C) 92	D) 93

Answer & Explanation Answer: A) 97

Explanation:

Marks in English = 85×7 – 83×6

= 595 – 498

= 97

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Filed Under: Average
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22 7988

Q:

P, Q and R start simultaneously from A to B. P reaches B, turns back and meet Q at a distance of 11 km from B. Q reached B, turns back and meet R at a distance of 9 km from B. If the ratio of the speeds of P and R is 3:2, what is the distance between A and B ?

A) 99	B) 100
C) 89	D) 1

Answer & Explanation Answer: A) 99

Explanation:

Let, Distance between A and B = d

Distance travelled by P while it meets Q = d + 11

Distance travelled by Q while it meets P = d – 11

Distance travelled by Q while it meets R = d + 9

Distance travelled by R while it meets Q = d – 9

Here the ratio of speeds of P & Q => SP : SQ = d + 11 : d – 11

The ratio of speeds of Q & R => SQ : SR = d + 9 : d – 9

But given Ratio of speeds of P & R => P : R = 3 : 2

$\frac{S P}{S R} = \frac{S P}{S Q} x \frac{S Q}{S R} = \frac{(d + 11) (d + 9)}{(d - 11) (d - 9)}$

=> $\frac{(d + 11) (d + 9)}{(d - 11) (d - 9)}$ = 3/2

=> d = 1, 99

=> d = 99 satisfies.

Therefore, Distance between A and B = 99

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Filed Under: Time and Distance
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16 7987

Q:

P and Q were assigned to do a work for an amount of 1200. P alone can do it in 15 days while Q can do it in 12 days. With the help of R they finish the work in 6 days. Find the share of R ?

A) 120	B) 240
C) 360	D) 180

Answer & Explanation Answer: A) 120

Explanation:

1/15 + 1/12 + 1/R = 1/6, we got R = 60 (it means R will take 60 days to complete the work alone)

so ratio of work done by P:Q:R = 1/15 : 1/12 : 1/60 = 5 : 4 : 1

so R share = (1/10) x 1200 = 120.

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Filed Under: Time and Work
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5 7984

Q:

A jar was full with honey. A person used to draw out 20% of the honey from the jar and replaced it with sugar solution. He has repeated the same process 4 times and thus there was only 512 gm of honey left in the jar, the rest part of the jar was filled with the sugar solution. The initial amount of honey in the jar was:

A) 1.25 kg	B) 1 kg
C) 1.5 kg	D) None of these

Answer & Explanation Answer: A) 1.25 kg

Explanation:

Let the initial amount of honey in the jar was k, then

$512 = k {(1 - \frac{1}{5})}^{4} o r 512 = k {(\frac{4}{5})}^{4}$

=> $k = \frac{512 \times 625}{256}$

=> k = 1250

Hence initially the honey in the jar = 1.25 kg

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Filed Under: Alligation or Mixture
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23 7978

Q:

An amount of money was lent for 3 years. What will be the difference between the simple and the compound interest earned on it at the same rate?
I. The rate of interest was 8 p.c.p.a.
II. The total amount of simple interest was Rs. 1200

A) I alone sufficient while II alone not sufficient to answer	B) alone sufficient while I alone not sufficient to answer
C) Both I and II are not sufficient to answer	D) Both I and II are necessary to answer

Answer & Explanation Answer: D) Both I and II are necessary to answer

Explanation:

Given: T = 3 years.
I. gives: R = 8% p.a.
II. gives: S.I. = Rs. 1200.
Thus, P = Rs. 5000, R = 8% p.a. and T = 3 years.
Difference between C.I. and S.I. may be obtained.
So, the correct answer is (D).

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Filed Under: Compound Interest
Exam Prep: Bank Exams
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0 7972

Q:

Given that 10^0.48 = x, 10^0.70 = y and x^z = y², then the value of z is close to ___ ?

A) 3.7	B) 2.7
C) 3.6	D) 2.9

Answer & Explanation Answer: D) 2.9

Explanation:

x^z = y² 10^(0.48z) = 10^{(2 x 0.70)} = 10^1.40

0.48z = 1.40

z = 140/18 = 35/12 = 2.9 (approx.)

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Filed Under: Simplification
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10 7969

Q:

In how many ways can the letters of the word 'LEADER' be arranged ?

A) 360	B) 420
C) 576	D) 220

Answer & Explanation Answer: A) 360

Explanation:

No. of letters in the word = 6
No. of 'E' repeated = 2
Total No. of arrangement = 6!/2! = 360

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Filed Under: Permutations and Combinations
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4 7968

Quantitative Aptitude - Arithmetic Ability Questions

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