6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A person got Rs.48 more when he invested a certain sum at compound interest instead of simple interest for two years at 8% p.a. Find the sum ?

A) Rs.8000	B) Rs.6500
C) Rs.7500	D) Rs.5000

Answer & Explanation Answer: C) Rs.7500

Explanation:

$p = \frac{(d \times 100^{2})}{R^{2}}$

Where d is difference, r is rate of interest.

=> (48 x 100 x 100) / 8 x 8 = Rs.7500

Report Error

View Answer Report Error Discuss

Filed Under: Simple Interest
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

6 7943

Q:

Ravi and Ramu are partners in a business.Ravi contributes 1/6 of the capital for 16 months and Ramu received 2/3 of the profit. For how long Ramu's money was used ?

A) 11 months	B) 10 months
C) 9 months	D) 8 months

Answer & Explanation Answer: D) 8 months

Explanation:

Let the total Profit be Z.
Ramu's profit share is 2/3 of profit (i.e 2Z/3)
Ravi's profit is (Z-2Z/3) =Z/3
Hence the profit ratio is , Ravi : Ramu = Z/3 : 2Z/3 = 1:2

Let total Capital be Rs.X and Ramu has contributed for Y months.Since Ramu's profit share is 2/3, his invest share will be 2/3 in capital.

Ravi's invest for 16 months / Ramu's invest for Y months = Ravi's profit share / Ramu's profit share
i.e. (X/6 x 16) / (2X/3 x Y) = 1/2

Solving the above equation, we get Y = 8.
So Ramu's money has been used for 8 months.

Report Error

View Answer Report Error Discuss

Filed Under: Partnership
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Bank Clerk , Bank PO

5 7939

Q:

What would be the least number of years in which the simple interest on Rs.2600 at % will be an exact number of rupees ?

A) 2	B) 3
C) 4	D) 5

Answer & Explanation Answer: B) 3

Explanation:

$S . I = R s . [2600 * \frac{20}{3} * \frac{1}{100} * t]$

$S . I = R s . [\frac{520}{3} * t]$

t=3

Report Error

View Answer Report Error Discuss

Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

6 7937

Q:

A, B and C can do a piece of work in 72, 48 and 36 days respectively. For first p/2 days, A & B work together and for next ((p+6))/3days all three worked together. Remaining 125/3% of work is completed by D in 10 days. If C & D worked together for p day then, what portion of work will be remained?

A) 1/5	B) 1/6
C) 1/7	D) 1/8

Answer & Explanation Answer: B) 1/6

Explanation:

Total work is given by L.C.M of 72, 48, 36

Total work = 144 units

Efficieny of A = 144/72 = 2 units/day

Efficieny of B = 144/48 = 3 units/day

Efficieny of C = 144/36 = 4 units/day

According to the given data,

2 x p/2 + 3 x p/2 + 2 x (p+6)/3 + 3 x (p+6)/3 + 4 x (p+6)/3 = 144 x (100 - 125/3) x 1/100

3p + 4.5p + 2p + 3p + 4p = 84 x 3 - 54

p = 198/16.5

p = 12 days.

Now, efficency of D = (144 x 125/3 x 1/100)/10 = 6 unit/day

(C+D) in p days = (4 + 6) x 12 = 120 unit

Remained part of work = (144-120)/144 = 1/6.

Report Error

View Answer Report Error Discuss

Filed Under: Time and Work
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Analyst , Bank Clerk , Bank PO , Database Administration , IT Trainer

7 7935

Q:

The compound interest on Rs. 30,000 at 7% per annum is Rs. 4347. The period (in years) is

A) 2years	B) 3years
C) 4years	D) 5years

Answer & Explanation Answer: A) 2years

Explanation:

Amount = Rs(30000 + 4347) = Rs.34347.

Let the time be n years. Then,

$30000 {[1 + \frac{7}{100}]}^{n} = 34347$

$\Leftrightarrow$ ${(\frac{107}{100})}^{n} = \frac{34347}{30000} = \frac{11449}{10000} = {(\frac{107}{100})}^{2}$

n= 2years.

Report Error

View Answer Report Error Discuss

Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

1 7932

Q:

In what ratio should two varieties of tea at Rs. 60 per kg and Rs.120 per kg be mixed together so that by selling the mixture at Rs.96 per kg, a profit of Rs.20% is obtained ?

Answer

Let us first calculate the cost of price of the mixture. the selling price of the mixture is given as Rs.96 and the profit is given as 20%. So, Cost price = $\frac{100}{120} \times 96$ = Rs. 80

Now, let us apply allegation method :

= 40 : 20 = 2 : 1

Workspace

Report Error

View answer Workspace Report Error Discuss

Subject: Alligation or Mixture

9 7929

Q:

K and L starts walking towards each other at 4 pm at speed of 3 km/hr and 4 km/hr respectively. They were initially 17.5 km apart. At what time do they meet ?

A) 6:00 am	B) 6:30 pm
C) 5:45 am	D) 5:52 pm

Answer & Explanation Answer: B) 6:30 pm

Explanation:

Suppose they meet after 'h' hours

Then

3h + 4h = 17.5

7h = 17.5

h = 2.5 hours

So they meet at => 4 + 2.5 = 6:30 pm

Report Error

View Answer Report Error Discuss

Filed Under: Time and Distance
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

12 7925

Q:

If Hema walks at 12 km/hr instead of 8 km/hr, she would have walked 20 km more. The actual distance travelled by Hema is ?

A) 40 kms	B) 30 kms
C) 46 kms	D) 32 kms

Answer & Explanation Answer: A) 40 kms

Explanation:

Let the actual distance travelled be x km.
Then x/8=(x+20)/12
=> 12x = 8x + 160
=> 4x = 160
=> x = 40 km.

Report Error

View Answer Report Error Discuss

Filed Under: Time and Distance
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

5 7910

Quantitative Aptitude - Arithmetic Ability Questions

Quick Links