6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:

A) 2:5	B) 3:5
C) 4:5	D) 5:4

Answer & Explanation Answer: C) 4:5

Explanation:

Let the third number be x.

Then, first number = 120% of x =120x/100 = 6x/5

Second number =150% of x = 150x/100 = 3x/2

Ratio of first two numbers = 6x/5 : 3x/2 = 12x : 15x = 4 : 5

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Filed Under: Ratios and Proportions

622 184098

Q:

Insert the missing number.

16, 33, 65, 131, 261, (....)

A) 523	B) 521
C) 613	D) 721

Answer & Explanation Answer: A) 523

Explanation:

Each number is twice the preceding one with 1 added or subtracted alternatively.

So, the next number is (2 x 261 + 1) = 523.

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Filed Under: Odd Man Out

45 170276

Q:

Simplify the following :

$\frac{37^{3} + 35^{3} + 28^{3} - 3 x 37 x 35 x 28}{37^{2} + 35^{2} + 28^{2} - 37 x 35 - 35 x 28 - 37 x 28}$ ?

A) 100	B) 1
C) 4	D) 0

Answer & Explanation Answer: A) 100

Explanation:

Given $\frac{37^{3} + 35^{3} + 28^{3} - 3 x 37 x 35 x 28}{37^{2} + 35^{2} + 28^{2} - 37 x 35 - 35 x 28 - 37 x 28}$

It is in the form of

$\frac{a^{3} + b^{3} + c^{3} - 3 a b c}{a^{2} + b^{2} + c^{2} - a b - b c - c a}$ = a + b + c

Here a = 37, b = 35 & c = 28

=> a + b + c = 37 + 35 + 28 = 100

Therefore, $\frac{(37)^{3}+(35)^{3}+(28)^{3}-3x37x35x28}{(37)^{2}+(35)^{2}+(28)^{2}-37x35-35x28-37x28}$ = 100

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Filed Under: Simplification
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

20 158383

Q:

If 20% of a = b, then b% of 20 is the same as :

A) 4% of a	B) 6% of a
C) 8% of a	D) 10% of a

Answer & Explanation Answer: A) 4% of a

Explanation:

20% of a = b

=> (20/100) * a = b

b% of 20 =(b/100) x 20 = [(20a/100) / 100] x 20= 4a/100 = 4% of a.

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Filed Under: Percentage
Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

1378 155779

Q:

$\sqrt[3]{9261} x \sqrt{62742241} = ? + 89$

Find the value of '?'

A) 166251	B) 166259
C) 166252	D) 166253

Answer & Explanation Answer: C) 166252

Explanation:

Given $\sqrt[3]{9261} x \sqrt{62742241} = ? + 89$

Using unit digit method,

On LHS,

1 x 1 x 1 = 1

sqrt of last digit 1 => it must end with either 9 or 1

so now

1 x 1 = 1

1 x 9 = 9

On RHS,

? + 89

=> ? = ...1 - 89 = last digit is 11- 9 = 2

or

=> ? = ...9 - 89 = last digit is 9 - 9 = 0

Here in the options last digit 2 is option C.

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Filed Under: Simplification
Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

22 155416

Q:

A student multiplied a number by 3/5 instead of 5/3, What is the percentage error in the calculation ?

A) 54 %	B) 64 %
C) 74 %	D) 84 %

Answer & Explanation Answer: B) 64 %

Explanation:

Let the number be x.

Then, ideally he should have multiplied by x by 5/3. Hence Correct result was x * (5/3)= 5x/3.

By mistake he multiplied x by 3/5 . Hence the result with error = 3x/5

Then, error = (5x/3 - 3x/5) = 16x/15

Error % = (error/True vaue) * 100 = [(16/15) * x/(5/3) * x] * 100 = 64 %

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Filed Under: Percentage

814 154838

Q:

Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?

A) 1/2	B) 3/5
C) 9/20	D) 8/15

Answer & Explanation Answer: C) 9/20

Explanation:

Here, S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}.

P(E) = n(E)/n(S) = 9/20.

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Filed Under: Probability

321 154430

Q:

A grocer has a sale of Rs 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs, 6500 ?

A) 4991	B) 5467
C) 5987	D) 6453

Answer & Explanation Answer: A) 4991

Explanation:

Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.

Required sale = Rs.[(6500 x 6) - 34009]

= Rs. (39000 - 34009)

= Rs. 4991.

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Filed Under: Average

401 152433

Quantitative Aptitude - Arithmetic Ability Questions

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