What will come in place of the question mark (?) in the following number series ?
12, 24, 26.5, 79.5, ?, 330
The given series
12 24 26.5 79.5 ? 330 follows a pattern that,
12 x 2 = 24
24 + 2.5 = 26.5
26.5 x 3 = 79.5
79.5 + 3 = 82.5
82.5 x 4 = 330
Hence, the missing number is 82.5
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39 persons can repair a road in 12 days, working 5 hours a day. In how many days will 30 persons, working 6 hours a day, complete the work?
Let the required number of days be x.
Less persons, More days (Indirect Proportion)
More working hours per day, Less days (Indirect Proportion)
Persons30:39Working hours/day6:5⋮⋮ 12:x
=> 30 * 6 * x = 39 * 5 * 12
=> x= 13
The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is:
Required number = H.C.F. of (1657 - 6) and (2037 - 5)
= H.C.F. of 1651 and 2032 = 127.
Find the missing number?
5 19 49 101 181 295 ?
Given number series is 5 19 49 101 181 295 ?
Here the series follows pattern that
14 30 52 80 114 (difference)
16 22 28 34 (difference)
6 6 6 (Common difference)
Therefore, the missing number in the series is ? = 295 + 115 + 34 + 6 = 449.
At what time between 7 and 8 o'clock will the hands of a clock be in the same straight line but,not together?
When the hands of the clock are in the same straight line but not together, they are 30 minute spaces apart.At 7 o'clock, they are 25 min. spaces apart.Minute hand will have to gain only 5 min. spaces.55 min. spaces are gained in 60 min.
5 min spaces are gained in 6055*5 min = 5511min
so, Required time = 5511 min past 7
Find the value of
n+3n2+9n4+......∞
On what dates of April, 2001 did Wednesday fall?
We shall find the day on 1st April, 2001.
1st April, 2001 = (2000 years + Period from 1.1.2001 to 1.4.2001)
Odd days in 1600 years = 0
Odd days in 400 years = 0
Jan. Feb. March April
(31 + 28 + 31 + 1) = 91 days 0 odd days.
Total number of odd days = (0 + 0 + 0) = 0
On 1st April, 2001 it was Sunday.
In April, 2001 Wednesday falls on 4th, 11th, 18th and 25th.
Find the next number in the following number series?
410, 409, 413, 404, ?
The given number series 410, 409, 413, 404, ? , follows a pattern that
410
410 - 13 = 409409 + 22 = 413413 - 33 = 404404 + 42 = 420
Hence, the next number in the given series is 420.