6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

K is 50% faster than L. If L starts at 9 A.M. and K starts at 10 A.M. L travels at a speed of 50 km/hr. If L and K are 300 kms apart, The time when they meet when they travel in opposite direction is ?

A) 12 pm	B) 1 pm
C) 11 am	D) 11:30 am

Answer & Explanation Answer: A) 12 pm

Explanation:

let 't' be the time after which they met since L starts.

Given K is 50% faster than L

50 t + 1.5*50(t-1) = 300

50 t +75 t = 300 + 75

t = 375 / 125 = 3 hrs past the time that L starts

So they meet at (9 + 3)hrs = 12:00 noon.

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Filed Under: Time and Distance
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4 7355

Q:

Kalyan purchased a Maruti van for Rs. 1,96,000 and the rate of depreciation is 14(2/7) % per annum. Find the value of the van after two years ?

A) Rs. 1,24,000	B) Rs. 1,44,000
C) Rs. 1,32,000	D) Rs. 1,62,000

Answer & Explanation Answer: B) Rs. 1,44,000

Explanation:

Value of Maruti Van, V1 = Rs. 1,96,000
Rate of depreciation, r = 14(2/7)% = 100/7%; Time, t = 2 years
Let V2 is the value after depreciation.

$V 2 = V 1 {(1 - (\frac{r}{100}))}^{t}$
V2 = $19600 {[1 - (\frac{\frac{100}{7}}{100})]}^{2}$

V2 = 196000(6/7)(6/7)

V2 = (196000x36)/49 = Rs. 1,44,000.

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Filed Under: Percentage
Exam Prep: GATE , CAT , Bank Exams , AIEEE
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4 7346

Q:

A bag contains 2 red Roses, 4 yellow Roses and 6 pink Roses. Two roses are drawn at random. What is the probability that they are not of same color?

A) 1/6	B) 2/3
C) 14/33	D) 5/6

Answer & Explanation Answer: B) 2/3

Explanation:

Possible outcomes = (RY, YP, PR)

2C1 4C1 + 4C1 6C1 + 6C1 2C1

Required probability = (2C1 4C1 + 4C1 6C1 + 6C1 2C1)/(12C2)

= 8 + 24 + 12/66

= 44/66

= 2/3.

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Filed Under: Probability
Exam Prep: AIEEE , Bank Exams , CAT
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54 7341

Q:

The marked price of a Watch is Rs.8400. It is to be sold at Rs.6896 at two successive discounts. If the first discount is 12%, the second discount is ?

A) 7.2 %	B) 9.14 %
C) 7.13 %	D) 6.709 %

Answer & Explanation Answer: D) 6.709 %

Explanation:

(100-x)% of 88% of 8400 = 6896

=> $\frac{100 - x}{100} (\frac{88}{100} x 8400) = 6896$

=> x = 6.709%

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Filed Under: Percentage
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4 7330

Q:

The banker's discount on Rs. 1650 due a certain time hence is Rs. 165. Find the true discount and the banker's gain.

A) 15	B) 20
C) 18	D) 13

Answer & Explanation Answer: A) 15

Explanation:

Sum = [(B.D.xT.D.)/ (B.D.-T.D.)]

= [(B.D.xT.D.)/B.G.]

T.D./B.G. = Sum/ B.D.

=1650/165

=10

Thus, if B.G. is Re 1, T.D. = Rs. 10.

If B.D.is Rs. ll, T.D.=Rs. 10.

If B.D. is Rs. 165, T.D. = Rs. [(10/11)xl65]

=Rs.150

And, B.G. = Rs. (165 - 150) = Rs, 15.

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Filed Under: Banker's Discount

6 7327

Q:

If (1 / 2.315) = 0.4319, find the value of (1 / 0.0002315).

A) 4319	B) 2315
C) 431.9	D) 231.5

Answer & Explanation Answer: A) 4319

Explanation:

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Filed Under: Decimal Fractions
Exam Prep: Bank Exams

2 7297

Q:

The mean of 100 observations is 40. It is found that an observation 84 was misread as 48. Then the correct mean is ?

A) 40.36	B) 41.24
C) 41.92	D) 42.05

Answer & Explanation Answer: A) 40.36

Explanation:

Given,

mean of 100 observations is 40

=> Total of 100 observations = 40 x 100 = 4000

84 is misread as 48

=> Difference = 84 - 48 = 36

=> Now, new total of 100 observations = 4000 + 36 = 4036

Correct Mean = 4036/100 = 40.36

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Filed Under: Average
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17 7287

Q:

A mixture contains 25% milk and rest water. What percent of this mixture must taken out and replaced with milk so that in mixture milk and water may become equal.

A) 31.8%	B) 31%
C) 33.33%	D) 29.85%

Answer & Explanation Answer: C) 33.33%

Explanation:

Now, take percentage of milk and applying mixture rule

25 100

50

50 25 = 2 : 1

Hence required answer = 1/3 or 33.33%

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Filed Under: Alligation or Mixture
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27 7280

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