Quantitative Aptitude - Arithmetic Ability Questions

18 Feb, 2016 = (2015 years + Period from 1.1.2016 to 18.2.2016)

Odd days in 1600 years = 0

Odd days in 400 years = 0

15 years = (12 ordinary years + 3 leap year) = (12 x 1 + 3 x 2)= 4 odd days

Jan  Feb

(31 + 18 ) = 49 days

49 days = (7 weeks + 0 day)= 0 odd day.

Total number of odd days = (0 + 0 + 4 + 0) = 4 odd day.

Given day is Thursday

since it is a combination = 38C17 = 2878 x 10^10

 4×3.14×r2 : 4×3.14×r2 = 1 : 2  

let the diagonals of the squares be 2x and 5x respectively

ratio of their areas = 12*2x2 :12*5x2= 4:25

Let the distance in one direction = k kms

Speed in still water = 4.5 kmph

Speed of river = 1.5

Hence, speed in upstream = 4.5 - 1.5 = 3 kmph

Speed in downstream = 4.5 + 1.5 = 6 kmph

Time taken by Rajesh to row upwards = k/3 hrs

Time taken by Rajesh to row downwards = k/6 hrs

Now, required Average speed =$$\begin{gathered} Total distanceTotal speed = 2kk3 + k6 \\ = 2k x 186k + 3k = 4 kmph \end{gathered}$$ 

Therefore, the average speed of the whole journey = 4kmph.

   0.125125...... = 0.125¯ =   125/999

The length of the longest pole which can be kept in a room 12 m long, 4 m broad and 3 m high is

=>  d2 = 122 + 42 + 32 = 13mts.