6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

$4 \frac{4}{5}$ of 259.99 = ? % of 1247.9

A) 96	B) 100
C) 78	D) 88

Answer & Explanation Answer: B) 100

Explanation:

Given

$4 \frac{4}{5}$ of 259.99 = ? % of 1247.9

24/5 x 260 = ? x 1248/100

? = 1248 x 100/1248

? = 100.

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Filed Under: Percentage
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6 4958

Q:

What is the rate of compound interest?
I. The principal was invested for 4 years.
II. The earned interest was Rs. 1491.

A) I alone sufficient while II alone not sufficient to answer	B) II alone sufficient while I alone not sufficient to answer
C) Either I or II alone sufficient to answer	D) Either I or II alone sufficient to answer

Answer & Explanation Answer: D) Either I or II alone sufficient to answer

Explanation:

Let Principal = Rs. P and Rate = R% p.a. Then,

Amount= $R s . [P {(1 + \frac{R}{100})}^{4}]$

C.I = $P [{(1 + \frac{R}{100})}^{4} - 1]$

$P [{(1 + \frac{R}{100})}^{4} - 1] = 1491$

Clearly, it does not give the answer

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Filed Under: Compound Interest
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0 4954

Q:

Select the odd number from the given alternatives.

A) 25	B) 49
C) 9	D) 8

Answer & Explanation Answer: D) 8

Explanation:

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Filed Under: Odd Man Out
Exam Prep: Bank Exams

0 4950

Q:

Navaneet has thrice the money Poonam has and Poonam has 25% more money than Hebah. If the average money of the three is Rs. 350, What is the amount that Navaneet has ?

A) Rs. 175	B) Rs. 220.75
C) Rs. 218.55	D) Rs. 656.25

Answer & Explanation Answer: D) Rs. 656.25

Explanation:

Assume Hebah has Rs. M

Since 25% more money at Poonam

=> Money at Poonam = M + (25% of M)

=> Money at Poonam = M + 0.25M = Rs. 1.25M

Money with Navaneet is thrice the money with Poonam,

=> Money at Navaneet = 3(1.25M) = Rs. 3.75M

Now, sum of all Money = (M + 1.25M + 3.75M) = Rs. 6M

But given the average of the money is Rs. 350

=> 6M/3 = 350

=> 2M = 350

=> M = 350/2 = Rs. 175

=> Amount of money Navaneet has = Rs. 3.75M = 3.75 x 175 = Rs. 656.25.

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Filed Under: Average
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22 4949

Q:

What is the square root of (√5 + 2)/(√5 – 2)?

A) √5 – √4	B) √5 + 2
C) 5 + √2	D) 7

Answer & Explanation Answer: B) √5 + 2

Explanation:

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Filed Under: Simplification
Exam Prep: Bank Exams

1 4948

Q:

Find the area of the square whose side is equal to the diagonal of a rectangle of length 3 cm and breadth 4 cm.

A) 25 sq.cm	B) 16 sq.cm
C) 9 sq.cm	D) 4 sq.cm

Answer & Explanation Answer: A) 25 sq.cm

Explanation:

Given length of the rectangle = 3 cm

Breadth of the rectangle = 4 cm

Then, the diagonal of the rectangle $D = \sqrt{3^{2} + 4^{2}} = \sqrt{25} = 5$

Then, it implies side of square = 5 cm

We know that Area of square = S x S = 5 x 5 = 25 sq.cm.

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Filed Under: Area
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18 4945

Q:

Ratio between heights of two cylinder in the ratio 3:5. Their volumes are in the ratio 27:80. Find ratio between their radius ?

A) 1:3	B) 2:1
C) 3:4	D) 4:7

Answer & Explanation Answer: C) 3:4

Explanation:

bank

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Filed Under: Volume and Surface Area
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14 4941

Q:

In what ratio must a merchant mix two varieties of oils worth Rs. 60/kg and Rs. 65/kg, so that by selling the mixture at Rs. 68.20/kg, he may gain 10% ?

A) 2:3	B) 4:3
C) 3:4	D) 3:2

Answer & Explanation Answer: D) 3:2

Explanation:

Let he mixes the oils in the ratio = x : y

Then, the cost price of the oils = 60x + 65y

Given selling price = Rs. 68.20

=> Selling price = 68.20(x+y)

Given profit = 10% = SP - CP

=> 10/100 (60x + 65y) = 68.20(x+y)-(60x + 65y)

=> 6x + 6.5y = 8.20x + 3.20y

=>2.2x = 3.3y

=> x : y = 3 : 2

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Filed Under: Alligation or Mixture
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17 4940

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