Quantitative Aptitude - Arithmetic Ability Questions

Q:

If the labour cost 20% of the cost of production and raw material cost 10% of the cost of production and the price on which article is sold is 20% above the cost of production. If the price of labour is increased by 40% and the price of raw material increased by 20% and rest other expenditure of cost remain constant. The industry thus decide to increase the selling price by 10%. Find the new profit percent  ?

A) 18% B) 20%
C) 22% D) 24%
 
Answer & Explanation Answer: B) 20%

Explanation:

Let the Cost of Production of the article = 100

Then, Labour Cost = 20

Raw Material = 10

Other Expenditure = 100 - 10 – 20 = 70

Selling Price of the article  = 120

After increasing Labour and Raw material cost by 40% & 20% respectively,

New Labour cost = 28

New Raw material cost = 12

New Cost of Production = 70 + 28 + 12 = 110

Then, New SP = 110% of 120 = 120 x 110/100 = 132

=> New Gain = 132 - 110 = 22

=> New Profit % = 22 x 100/110 = 20%

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Q:

The sum of one-half, one-third and one-fourth of a number exceeds the number by 22. The number is

A) 264 B) 284
C) 215 D) 302
 
Answer & Explanation Answer: A) 264

Explanation:

Let the number be 'x'. Then, from given data

x/2 + x/3 + x/4 = x+22
13x/12 = x+22
x = 264

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4 7040
Q:

A man spend 20% of his monthly salary on his children's education and 50% of his salary on food and transport. After Paying the rent of Rs.1000, he is left with Rs.2000. What is his monthly salary?

A) 7000 B) 10000
C) 14000 D) 20000
 
Answer & Explanation Answer: B) 10000

Explanation:

Let his monthly salary be 'P'

20% on children's education = 20P100 = P5

50% on food and transport = 50P100 = P2

1000 on rent

=> P - P5 - P2 - 1000 = 2000=> 3P = 30000=> P = 10000

 

Therefore, his monthly salary = Rs. 10,000

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4 7040
Q:

P, Q and R secured 45%, 50% and 60% marks respectively in Biology. M’s marks in Biology is 12.5 more than P’s marks and 4 less than R’s marks. Find out the individual marks of four students.

 

A. For the students, total marks obtained for Biology is 311.5.
B. Total of M’s and P’s marks in Biology is 147.5.
C. R has obtained 84 marks.

A) Only C B) Only A & B
C) All are required D) None of the statements is required
 
Answer & Explanation Answer: D) None of the statements is required

Explanation:

From the given data,
(60 - 45)% = 12.5 + 4
15% = 16.5
=> 100% = ?
100% = 16.5 x 100/15 = 110

Hence, P = 45% of 110 = 45x110/100 = 49.5
Q = 50% of 110 = 55
R = 60% of 110 = 60 x 110/100 = 66
M = 12.5 + 49.5 = 62 or 66 - 4 = 62

 

Hence, no statement is required to answer.

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3 7035
Q:

A circular piece of thin wire is converted into a rhombus of side 11 cm. Find the diameter of the circular piece?

A) 28 cm B) 3.5 cm
C) 7 cm D) 14 cm
 
Answer & Explanation Answer: D) 14 cm

Explanation:

Circular piece is 4 x 11 = 44 cm long,

Then Circumference of circle is given by,

44 = pi x D, where D is the diameter

D = 44 / pi

Take pi = 22 / 7, then

D = 44 / (22/7) = (44 x 7) / 22

D = 14 cm.

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24 7034
Q:

If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to ?

A) 13/125 B) 14/57
C) 11/120 D) 16/41
 
Answer & Explanation Answer: C) 11/120

Explanation:

Let the numbers be a and b.
We know that product of two numbers = Product of their HCF and LCM
Then, a + b = 55 and ab = 5 x 120 = 600.
=> The required sum = (1/a) + (1/b) = (a+b)/ab
=55/600 = 11/120

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Filed Under: HCF and LCM
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23 7027
Q:

A teacher multiplies 987 by a certain number and obtains 556781 as her answer. If in the answer, both 6 and 7 are wrong but the other digits are correct, then the correct answer will be

A) 553681 B) 555181
C) 556581 D) 555681
 
Answer & Explanation Answer: D) 555681

Explanation:

Given number is 987 = 3 x 7 x 47.

So, required number must be divisible by each one of 3, 7, 47.

None of the numbers in 553681 and 555181 are divisible by 3. While 556581 is not divisible by 7.
Correct answer is 555681.

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7 7016
Q:

A man has only 20-paise and 25-paise coins in a bag. If he has 50 coins in all totaling to Rs.10.25, then the number of 20-paise coins is 

A) 42 B) 45
C) 38 D) 36
 
Answer & Explanation Answer: B) 45

Explanation:

Let number of 20 ps coins = x and

number of 25 ps coins = y

Given total coins in the bag = 50

x + y = 50.......(1)

But the total money in the bag = Rs. 10.25

0.20x + 0.25y = 10.25

20x + 25y = 1025.........(2)

Now multiplying (1) by 25 we get

25x+25y=1250.............(3)

By solving (2) and (3)

20x + 25y = 1025;

=> x = 45;

Then, the no. of 20 ps coins are 45.

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