Quantitative Aptitude - Arithmetic Ability Questions

Q:

The probability that a number selected at random from the first 100 natural numbers is a composite number is  ?

A) 3/2 B) 2/3
C) 1/2 D) 34/7
 
Answer & Explanation Answer: A) 3/2

Explanation:

The number of exhaustive events = 100 C₁ = 100.

We have 25 primes from 1 to 100.

Number of favourable cases are 75.

Required probability = 75/50 = 3/2.

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Filed Under: Probability
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13 6718
Q:

A school has scheduled three volleyball games, two soccer games, and four basketball games. You have a ticket allowing you to attend three of the games. In how many ways can you go to two basketball games and one of the other events?

A) 25 B) 30
C) 50 D) 75
 
Answer & Explanation Answer: B) 30

Explanation:

Since order does not matter it is a combination. 

 

The word AND means multiply. 

 

Given 4 basketball, 3 volleyball, 2 soccer. 

 

We want 2 basketball games and 1 other event. There are 5 choices left. 

C(n,r) 

C(How many do you have, How many do you want) 

C(have 4 basketball, want 2 basketball) x C(have 5 choices left, want 1) 

C(4,2) x C(5,1) = (6)(5) = 30

 

Therefore there are 30 different ways in which you can go to two basketball games and one of the other events.

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1 6717
Q:

In what time a 360 m. long train moving at the speed of 44 km/hr will cross a 140 m. long bridge ?

A) 36 sec B) 39 sec
C) 41 sec D) 43 sec
 
Answer & Explanation Answer: C) 41 sec

Explanation:

Speed = 44 kmph x 5/18 = 110/9 m/s

We know that, Time = distance/speed

Time = (360 + 140) / (110/9)

= 500 x 9/110 = 41 sec.

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Filed Under: Time and Distance
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12 6715
Q:

Ten years ago, A was half of B in age. If the ratio of their present ages is 3:4, then what will be the total of their present ages?

Answer

Let A's age 10 years ago be x years 


Then B's age 10 years ago  be 2x yeats


\inline \Rightarrow \frac{x+10}{2x+10}=\frac{3}{4}


\inline \Rightarrow 4(x+10)=3(2x+10)


\inline \Rightarrow x=5


\inline \therefore Total of their present ages =                                        


                                          = 


                                          = 35 years

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Subject: Problems on Ages

9 6715
Q:

The profit earned by selling an article for Rs.753 is equal to the loss incurred when the same article is sold for Rs.455.What should be the sale price for making 50% profit ?

A) Rs.855 B) Rs.955
C) Rs.906 D) Rs.896
 
Answer & Explanation Answer: C) Rs.906

Explanation:

Let C.P =Rs. x

 

Then as given, (753 - x ) = (x - 455)

=>2x = 1208 => x = 604

 There fore S.P= 150% of 604 => Rs. 150100×604= Rs.906

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Filed Under: Profit and Loss
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14 6711
Q:

One year ago the ratio between Mohan and Ashok's age was 4:3 after one yerar the rato of their ages will be 5:4 . what is the sunm of their present ages in years.

Answer

Let their ages one year  ago be 4x and 3x years


  


   


 Sum of their present ages =(4x +1+3x+1) = 16 years.

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Subject: Problems on Ages

6 6710
Q:

A merchant commences with a certain capital and gains annually at the rate of 30 per cent. At the end of 2 years he has worth Rs 10,000. What was the original capital? 

A) Rs. 4987 B) Rs. 5148
C) Rs. 5917 D) Rs. 6254
 
Answer & Explanation Answer: C) Rs. 5917

Explanation:

Let the Original capital amount be Rs. P

Given after 2 years the amount is Rs. 10000

Rate of interest = 30%

According to the question,

P x 130100 x 130100 = 10000=> P = 1000000169 = 5917

Therefore, the capital amount P = Rs. 5917

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Filed Under: Percentage
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6 6700
Q:

The ratio of present ages of Hema and Chinnu is 13:17. Four years ago the ratio of their ages was 11:15. What will be the ratio of their ages six years hence ?

A) 3 : 7 B) 7 : 9
C) 4 : 5 D) 1 : 3
 
Answer & Explanation Answer: C) 4 : 5

Explanation:

Let their present ages be 13x and 17x.
Then, 13x-4/17x-4 = 11/15.
Solving this, we get x = 2.
Required ratio = 13x2 + 6/17x2 + 6 = 32/40 = 4/5.

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Filed Under: Problems on Ages
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