6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

One year ago the ratio between Mohan and Ashok's age was 4:3 after one yerar the rato of their ages will be 5:4 . what is the sunm of their present ages in years.

Answer

Let their ages one year ago be 4x and 3x years

$\Rightarrow \frac{4x+2}{3x+2}=\frac{5}{4}\Rightarrow 4(4x+2)=5(3x+2)$

$\Rightarrow x=2$

$\therefore$ Sum of their present ages =(4x +1+3x+1) = 16 years.

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Subject: Problems on Ages

6 6868

Q:

When six fairs coins are tossed simultaneously, in how many of the outcomes will at most three of the coins turn up as heads ?

A) 15	B) 42
C) 16	D) 40

Answer & Explanation Answer: B) 42

Explanation:

The question requires you to find number of the outcomes in which at most 3 coins turn up as heads.

i.e., 0 coins turn heads or 1 coin turns head or 2 coins turn heads or 3 coins turn heads.

The number of outcomes in which 0 coins turn heads is $6 C_{0}$ =1

The number of outcomes in which 1 coin turns head is = $6 C_{1}$ =6

The number of outcomes in which 2 coins turn heads is $6 C_{2}$ =15

The number of outcomes in which 3 coins turn heads is $6 C_{3}$ =20

Therefore, total number of outcomes =1+6+15+20= 42 outcomes

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Filed Under: Permutations and Combinations

3 6865

Q:

A sum of Rs. 8,000 is deposited for 3 years at 5% per annum compound interest (compounded annually). The difference of interest for 3 years and 2 years will be

A) Rs. 387	B) Rs. 441
C) Rs. 469	D) Rs. 503

Answer & Explanation Answer: B) Rs. 441

Explanation:

Given principal amount = Rs. 8000

Time = 3yrs

Rate = 5%

C.I for 3 yrs = $8000 x \frac{105}{100} x \frac{105}{100} x \frac{105}{100} - 8000 = Rs . 1261$

Now, C.I for 2 yrs = $8000 x \frac{105}{100} x \frac{105}{100} = Rs . 820$

Hence, the required difference in C.I is 1261 - 820 = Rs. 441

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Filed Under: Compound Interest
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14 6862

Q:

A train is moving and crossing a man who is running on a platform of 100 m at a speed of 8 kmph in the direction of the train, in 9 sec. If the speed of the train is 74 kmph. Find the length of the train ?

A) 202 mts	B) 188 mts
C) 165 mts	D) 156 mts

Answer & Explanation Answer: C) 165 mts

Explanation:

Let the length of the train = L mts

Relative speed of train and man = 74 - 8 = 66 kmph = 66 x 5/18 m/s

=> 66 x 5/18 = L/9

=> L = 165 mts.

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Filed Under: Problems on Trains
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22 6855

Q:

Find out the wrong term in the given series of numbers ?
6, 15, 35, 77, 165, 221

A) 35	B) 165
C) 221	D) 77

Answer & Explanation Answer: B) 165

Explanation:

The given series follow the rule that :

Multiplying consecutive prime numbers
2,3,5,7,11,13,17,19....
2x3 = 6
3x5 = 15
5x7 = 35
7x11 = 77
11x13 = 143
13x17 = 221
So, the wrong term is 165.

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Filed Under: Odd Man Out
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6 6853

Q:

Den Bosch and Eastbourne are two famous cities 300 km apart. Maradona starts from Den Bosch at 8:24 am . An hour later pele starts from Den Bosch. After travelling for 1 hour , Pele reaches Nottingham that Maradona had passed 40 minutes earlier. Nottingham falls on the way from Den Bosch to Eastbourne. If pele and Maradona just reaches Eastbourne at the same time, what are thespeeds of the Maradona and Pele Respectively?

A) 100 km/h , 125 km/h	B) 60 km/h , 80 km/h
C) 60 km/h , 75 km/h	D) 75 km/h , 100 km/h

Answer & Explanation Answer: D) 75 km/h , 100 km/h

Explanation:

Let Pele x km in 1 hour. so Maradona takes (2h-40min)=1 h 20 min to cover x km. Let speed of Maradona and Pele be M and P respectively than

x =M x (4/3) and x= P x 1

=> M/P = 3/4

Again $\frac{300}{M} = \frac{300}{P} = 1$

$\Rightarrow \frac{300}{3 k} - \frac{300}{4 k} = 1$

=> k= 25

M= 3k = 75 km/h and P= 4k = 100 km/h

( Through options it is very easy to solve)

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Filed Under: Time and Distance

9 6849

Q:

A class has 8 football players. A 5-member team and a captain will be selected out of these 8 players. How many different selections can be made ?

A) 210	B) 168
C) 1260	D) 10!/6!

Answer & Explanation Answer: B) 168

Explanation:

we can select the 5 member team out of the 8 in 8C5 ways = 56 ways.

The captain can be selected from amongst the remaining 3 players in 3 ways.

Therefore, total ways the selection of 5 players and a captain can be made = 56x3 = 168 ways.

(or)

Alternatively, A team of 6 members has to be selected from the 8 players. This can be done in 8C6 or 28 ways.

Now, the captain can be selected from these 6 players in 6 ways.

Therefore, total ways the selection can be made is 28x6 = 168 ways.

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Filed Under: Permutations and Combinations
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8 6832

Q:

On her deathbed, a grand mother called upon his three grand sons and told them to distribute all her assets worth Rs. 52,500 in the ratio of 1/35 : 1/21 : 1/15 amongst themselves. Find the smallest share amongst the three portions ?

A) Rs. 5422	B) Rs. 10,500
C) Rs. 12,800	D) Rs. 15,000

Answer & Explanation Answer: B) Rs. 10,500

Explanation:

The ratio of distribution should be:
21 x 15 : 15 x 35 : 35 x 21
= 315 : 525 : 735
= 3 : 5 : 7
The smallest share will be of worth:
3/15 x 52,500 = Rs. 10,500

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Filed Under: Ratios and Proportions
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6 6831

Quantitative Aptitude - Arithmetic Ability Questions

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