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 Quantitative Aptitude - Arithmetic Ability Questions

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Q:

A sales boy is allowed 412 % discount on the total sales made by him plus a bonus of 14% on the sales over Rs.12,000.If his total earnings were Rs.2400, then his total sales(in Rs.) are ?

A) Rs.60,145.23 B) Rs.54,285.54
C) Rs.52,147.85 D) Rs.50,589.47
 
Answer & Explanation Answer: D) Rs.50,589.47

Explanation:

Let the total earnings be Rs.x 

Then 412% of x + 14% of (x-12000) =2400

 ⇒92×x100+14×x-12000100=2400

=>  x=50,589.47

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Filed Under: Percentage
Exam Prep: CAT
Job Role: Bank Clerk

8 6758
Q:

The average age of seven persons sitting in a row facing east is 26 years. If the average age of the first three persons is 19 years and the average age of the last three persons is 32 years, then find the age of the person sitting in the middle of the row ?

A) 32 yrs B) 29 yrs
C) 24 yrs D) 27 yrs
 
Answer & Explanation Answer: B) 29 yrs

Explanation:

Total age seven persons = (26 x 7)years
Total age of the first three persons and the last three persons are (19 x 3) years and (32 x 3) years respectively.
Age of the person sitting in the middle of the row = 26 x 7 - 19 x 3 - 32 x 3 = 182 - 57 - 96 = 29 years.

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Filed Under: Problems on Ages
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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5 6757
Q:

Munna and Chinna are partners in a firm out of which Munna is sleeping partner and Chinna is working partner. Munna invests Rs. 1,40,000 and Chinna invests Rs. 80,000. Chinna receives 14.5% of profit for managing the business and the rest is shared between both in ratio of their investments. Munna's share in the profit of Rs. 19600 is ?

A) Rs. 9580.25 B) Rs. 10600
C) Rs. 10664.15 D) Rs. 11060.48
 
Answer & Explanation Answer: C) Rs. 10664.15

Explanation:

Profit received by Chinna as working partner = 14.5% of Rs. 19600

= 14.5x19600/100 = Rs. 2842

Balance in profit = 19600-2842 = Rs. 16758

Ratio of investment of Chinna & Munna = 80,000 : 1,40,000 = 4 : 7

Hence share of Chinna in investment = 4x16758/100 = Rs. 6093.85

Therefore, Share of Munna = 19600 - 2842 - 6093.85 = Rs. 10664.15

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Filed Under: Partnership
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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7 6756
Q:

The average age of the district level hockey team of eleven is 22 years.The average age gets increased by 1 year when the coach age is also included.what is the age of the coach ?

A) 33 yrs B) 34 yrs
C) 35 yrs D) 36 yrs
 
Answer & Explanation Answer: B) 34 yrs

Explanation:

Total age of players in team = 22 x 11 = 242
When coach is included, total members = 12, Avg age increases by one becomes 23
Total age when coach is included = 23x12 = 276
Age of coach = 276-242 = 34 yrs.

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Filed Under: Average
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4 6749
Q:

Ten years ago, A was half of B in age. If the ratio of their present ages is 3:4, then what will be the total of their present ages?

Answer

Let A's age 10 years ago be x years 


Then B's age 10 years ago  be 2x yeats


\inline \Rightarrow \frac{x+10}{2x+10}=\frac{3}{4}


\inline \Rightarrow 4(x+10)=3(2x+10)


\inline \Rightarrow x=5


\inline \therefore Total of their present ages =                                        


                                          = 


                                          = 35 years

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Subject: Problems on Ages

9 6747
Q:

In how many ways can 5 different toys be packed in 3 identical boxes such that no box is empty, if any of the boxes may hold all of the toys?

A) 15 B) 10
C) 25 D) 20
 
Answer & Explanation Answer: C) 25

Explanation:

The toys are different; The boxes are identical
If none of the boxes is to remain empty, then we can pack the toys in one of the following ways
a. 2,2,1
b. 3,1,1

Case a. Number of ways of achieving the first option 2−2–1

Two toys out of the 5 can be selected in5C2 5 ways. Another 2 out of the remaining 3 can be selected in3C2 ways and the last toy can be selected in 1C1  way.

However, as the boxes are identical, the two different ways of selecting which box holds the first two toys and which one holds the second set of two toys will look the same. Hence, we need to divide the result by 2.

Therefore, total number of ways of achieving the 2−2–1 option is:

5C2*3C22=10*32=15 ways.

Case b. Number of ways of achieving the second option 3−1–1

Three toys out of the 5 can be selected in 5C3  ways. As the boxes are identical, the remaining two toys can go into the two identical looking boxes in only one way.
Therefore, total number of ways of getting the 3−1–1 option is5C3=10 ways.

Total ways in which the 5 toys can be packed in 3 identical boxes
=number of ways of achieving Case a + number of ways of achieving Case b
=15 + 10 = 25 ways

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Filed Under: Permutations and Combinations

0 6744
Q:

A 260 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train  ?

A) 240 mts B) 270 mts
C) 260 mts D) 250 mts
 
Answer & Explanation Answer: A) 240 mts

Explanation:

Relative speed = 120 + 80 = 200 km/hr.
= 200 x 5/18 = 500/9 m/sec.

Let the length of the other train be L mts.
Then, (L + 260)/9 = 500/9 => L = 240 mts.

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Filed Under: Problems on Trains
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3 6744
Q:

A car is purchased on hire-purchase. The cash price is $21 000 and the terms are a deposit of 10% of the price, then the balance to be paid off over 60 equal monthly instalments. Interest is charged at 12% p.a.  What is the monthly instalment?

A) $503 B) $504
C) $505 D) %506
 
Answer & Explanation Answer: B) $504

Explanation:

Cash price = $21 000

Deposit = 10% × $21 000 = $2100 

Loan amount = $21000 − $2100 = $18900

I=p x r x t/100 

I=11340

Total amount = 18900 + 11340 = $30240

Regular payment = total amount /number of payments

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Filed Under: Simple Interest
Exam Prep: Bank Exams
Job Role: Bank PO

7 6726