6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

The cost price of three varieties of mangoes namely M, N and O is Rs. 20/kg, Rs. 40/kg and Rs. 50/kg respectively. Find the selling price of one kg of mango in which these three varieties of mangoes are mixed in the ratio of 2 : 3 : 5 such that there is a net profit of 20%?

A) Rs. 47	B) Rs. 49.2
C) Rs. 48.5	D) Rs. 50.3

Answer & Explanation Answer: B) Rs. 49.2

Explanation:

Total cost of all varieties of mangoes = 20 x 2 + 40 x 3 + 50 x 5 = 40 + 120 + 250 = Rs. 410

Then, cost of 1 kg mangoes = 410/10 = Rs. 41

To get 20% profit,

The rate at which the mangoes should be sell = 120/100 x 41 = Rs. 49.2

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Filed Under: Profit and Loss
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15 6218

Q:

If the sum of two numbers is 55 and the H.C.F and L.C.M of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to

A) 55/601	B) 601/55
C) 11/120	D) 120/11

Answer & Explanation Answer: C) 11/120

Explanation:

Let the numbers be a and b . Then, a+b =55 and ab = 5 x 120 = 600.

Therefore, Required sum = $\frac{1}{a} + \frac{1}{b} = \frac{a + b}{a b} = \frac{55}{600} = \frac{11}{120}$

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Filed Under: HCF and LCM

7 6210

Q:

In an old Palace there are 50 stairs to go on top floor. Each is 20 cm high, 30 cm wide and 60 cm long. If all the stairs are re-plastered at the rate of Rs. 4 per 100 sq.cm. What is the expenditure ?

A) Rs. 4680	B) Rs. 7600
C) Rs. 6000	D) Rs. 5480

Answer & Explanation Answer: C) Rs. 6000

Explanation:

Total are of all stairs = 50 (20x60 + 30x60)

= 50 (1200 + 1800)

= 50 x 3000

= 150000 sq cm.

Given rate of 100 sq cm = Rs. 4

Then for 150000 sq. cm = ?

=> 4 x 150000/100 = Rs. 6000

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Filed Under: Area
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11 6208

Q:

From the following years,which is not a leap year ?

A) 1996	B) 1984
C) 1863	D) 2004

Answer & Explanation Answer: C) 1863

Explanation:

NOTE: When a year leaves a remainder 0 when divided by 4,then it is a leap year.

Here, 1863 divided by 4 doesnot give a remainder 0.

So, 1863 is not a leap year.

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Filed Under: Calendar

6 6206

Q:

If $\log_{3} (30)$ = $\frac{1}{a}$ and $\log_{5} (30) = \frac{1}{b}$ then the value of $3 \log_{30} (2)$ is:

A) 3(1+a+b)	B) 2(1-a-b)
C) 3(1-a-b)	D) 3(1+a-b)

Answer & Explanation Answer: C) 3(1-a-b)

Explanation:

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Filed Under: Logarithms
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25 6204

Q:

A tank is filled in eight hours by three pipes K, L and M. Pipe K is twice as fast as pipe L, and L is twice as fast as M. How much time will pipe L alone take to fill the tank ?

A) 32 hrs	B) 24 hrs
C) 28 hrs	D) 26 hrs

Answer & Explanation Answer: C) 28 hrs

Explanation:

1/K + 1/L + 1/M = 1/8 (Given)
Also given that K = 2L and L = 2M
=> 1/2L + 1/L + 2/L = 1/8
=> (1 + 2 + 4)/2L = 1/8
=> 2L/7 = 8
=> L = 28 hours.

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Filed Under: Pipes and Cistern
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8 6198

Q:

Application of Inverse Proportion

If 20 persons can do a piece of work in 7 days then calculate the number of persons require to complete the work in 28 days

Answer

Number of persons * days = work

20 * 7 = 140 man- days

Now, x * 28 = 140 men- days

=> x =5

Therefore in second case the required number of person is 5.

Second method:

Since work is constant, therefore M1 x D1= M2 x D2

20 x 7 = M2 x 28

=> M2 = 5

Workspace

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Subject: Time and Work

5 6186

Q:

The capacity of a tank is 2400 $m^{3}$ . A pump can be used both for filling and emptying the tank. The emptying capacity of the pump is 10 $m^{3}$ /minute higher than its filling capacity. And also, the pump needs 8 minutes less to empty the tank than to fill it. Find the filling capacity of the pump.

A) 46 cub.m/min	B) 44 cub.m/min
C) 48 cub.m/min	D) 50 cub.m/min

Answer & Explanation Answer: D) 50 cub.m/min

Explanation:

Let filling capacity of the pump be 'F' $m^{3} / \min$

Then, the filling capacity of the pump will be (F + 10) $m^{3} / \min$

From the given data,

$\frac{2400}{F} - \frac{2400}{F + 10} = 8 \Rightarrow 2400 [\frac{F + 10 - F}{F (F + 10)}] = 8 \Rightarrow F^{2} + 10 F - 3000 = 0 \Rightarrow F = 50 m^{3} / \min$

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Filed Under: Pipes and Cistern
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15 6159

Quantitative Aptitude - Arithmetic Ability Questions

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