6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A jogger running at 9 kmph alongside a railway track is 240 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger ?

A) 10 sec	B) 48 sec
C) 36 sec	D) 56 sec

Answer & Explanation Answer: C) 36 sec

Explanation:

Given speed of jogger = 9 kmph
Speed of train = 45 kmph
As they are in same direction,
Relative speed = 45 - 9 = 36 kmph = 36x5/18 = 10 m/s
Distance = 240 + 120 = 360 mts
Time = distance/speed = 360/10 = 36 sec.

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Filed Under: Problems on Trains
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2 5903

Q:

The Number of times the digit 8 will be written when listing the integers from 1 to 1000 is :

A) 100	B) 200
C) 300	D) 400

Answer & Explanation Answer: C) 300

Explanation:

Since 8 does not occur in 1000, we have to count the number of times 8 occurs when we list the integers from 1 to 999. Any number between 1 and 999 is of the form xyz, where $0 \leq x, y, z \leq 9 .$

Let us first count the numbers in which 8 occurs exactly once.

Since 8 can occur atone place in $3 C_{1}$ ways. There are $3 x 9 x 9$ such numbers.

Next, 8 can occur in exactly two places in $3 C_{2} \times 9$ such numbers. Lastly, 8 can occur in all three digits in one number only.

Hence, the number of times 8 occur is

$1 \times (3 \times 9^{2}) + 2 \times (3 \times 9) + 3 \times 1 = 300$

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Filed Under: Permutations and Combinations

2 5900

Q:

The difference between 4632 and 20000 is what number

A) 15368	B) 12652
C) 14562	D) 14965

Answer & Explanation Answer: A) 15368

Explanation:

The difference between 4632 and 20000 is given by subtracting smaler number from the bigger number.

Here the bigger number is 20000

Smaller number is 4632

Now, subtracting 4632 from 20000

20000 - 4632 = 15368 and the resut is an even number.

Hence, The difference between 4632 and 20000 is 15368 and is an even number.

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Filed Under: Problems on Numbers
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0 5900

Q:

Find the area of the rectangle or square with the given dimensions s=10 feet

A) 500	B) 100
C) 200	D) 300

Answer & Explanation Answer: B) 100

Explanation:

$A = S^{2}$

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

1 5893

Q:

In how many ways the letters of the word NUMERICAL can be arranged so that the consonants always occupy the even places ?

A) 5!	B) 6!
C) 4!	D) Can't determine

Answer & Explanation Answer: D) Can't determine

Explanation:

NUMERICAL has 9 positions in which 2, 4, 6, 8 are even positions.

And it contains 5 consonents i.e, N, M, R, C & L. Hence this cannot be done as 5 letters cannot be placed in 4 positions.

Therefore, Can't be determined.

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Filed Under: Permutations and Combinations
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6 5892

Q:

Sushma joins a job at 20 yrs. First 3 years salary is 10,000 p.a. Afterwards every year increment of 2,000 per year for 10 years. Then salary becomes constant till retirement. At retirement average salary is 25,000. (throughout career). At what age Sushma retires ?

A) 50 yrs	B) 47 yrs
C) 45 yrs	D) 42 yrs

Answer & Explanation Answer: A) 50 yrs

Explanation:

Let age of retirement = S
so according to the given condition 25000(x-20)
=10000 x 3 + 12000 + 14000 + 16000 + 18000 + 20000 + 22000 + 24000 + 26000 + 28000 + 30000 + 30000(S-33)
= 30000 + 210000 + 30000S-990000
= 30000S - 750000
or 25000S - 500000 = 30000x - 750000
or 5000x = 250000
or S = 50 yrs.

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Filed Under: Problems on Ages
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4 5891

Q:

The number of ways that 7 teachers and 6 students can sit around a table so that no two students are together is

A) 7! x 7!	B) 7! x 6!
C) 6! x 6!	D) 7! x 5!

Answer & Explanation Answer: B) 7! x 6!

Explanation:

The students should sit in between two teachers. There are 7 gaps in between teachers when they sit in a roundtable. This can be done in $7 P_{6}$ ways. 7 teachers can sit in (7-1)! ways.

Required no.of ways is = $7 P_{6} . 6! = 7! . 6!$

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Filed Under: Permutations and Combinations
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10 5883

Q:

Nine different letters of alphabet are given, words with 5 letters are formed from these given letters. Then, how many such words can be formed which have at least one letter repeated ?

A) 43929	B) 59049
C) 15120	D) 0

Answer & Explanation Answer: A) 43929

Explanation:

Number of words with 5 letters from given 9 alphabets formed = $9^{5}$

Number of words with 5 letters from given 9 alphabets formed such that no letter is repeated is = $9 P_{5}$

Number of words can be formed which have at least one letter repeated = $9^{5} - 9 P_{5}$

= 59049 - 15120

= 43929

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Filed Under: Permutations and Combinations
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11 5882

Quantitative Aptitude - Arithmetic Ability Questions

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