6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A girl read 2/5 part of a book in 1st day, 34% in second day and remaining page in next two days. In two days she read equal number of page. If she read 52 pages on last day, then find out how many pages did the book contain?

A) 400	B) 376
C) 382	D) 356

Answer & Explanation Answer: A) 400

Explanation:

1st day the girl read = 40%

2nd day she read = 34 %

Remaining percentage of book = 100% - (40% +34%) = 26%

But given last two days she read equal number of pages

=> Each day she read 26%/2 = 13%

Last day she read 52 pages = 13%

13% = 52

1% = 4

=> 100% = 400

Total pages in the book is 400.

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12 5876

Q:

The question given below contain two statements giving certain data. You have to decide whether the data given in the statements are sufficient for answering the question ?

Question :

What is the height of a right-angled triangle ?

Statements :

A. The area of the triangle is 20 times its base.

B. The perimeter of the triangle is equal to that of a square of the side 10 cm.

A) Only statement A is required	B) Only statement B is required
C) Both A & B are required	D) Neither (A) nor (B) is reuired

Answer & Explanation Answer: A) Only statement A is required

Explanation:

From statement (A),

20b = (1/2) × b × h

h = 40 cm.

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Filed Under: Area
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27 5876

Q:

Find the area of the square whose side is equal to the diagonal of a rectangle of length 3 cm and breadth 4 cm.

A) 25 sq.cm	B) 16 sq.cm
C) 9 sq.cm	D) 4 sq.cm

Answer & Explanation Answer: A) 25 sq.cm

Explanation:

Given length of the rectangle = 3 cm

Breadth of the rectangle = 4 cm

Then, the diagonal of the rectangle $D = \sqrt{3^{2} + 4^{2}} = \sqrt{25} = 5$

Then, it implies side of square = 5 cm

We know that Area of square = S x S = 5 x 5 = 25 sq.cm.

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18 5874

Q:

If the average height of boys in a hall is 180 cm and that of girls is 150 cm. If the average height of the gathering is 165 cm, then find the number of girls present in the hall if the number of boys present in the hall are 78 ?

A) 56	B) 64
C) 87	D) 78

Answer & Explanation Answer: D) 78

Explanation:

Using Trial and error method,

we get the number of girls in the hall = 78

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Filed Under: Average
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27 5869

Q:

In a 100 litre of mixture the ratio of milk and water is 6:4. How much milk must be added to the mixture in order to make the ratio 3 : 1?

A) 85	B) 60
C) 55	D) 45

Answer & Explanation Answer: B) 60

Explanation:

Let M litres milk be added

=> $\frac{60 + M}{40} = \frac{3}{1}$

=> 60 + M = 120

=> M = 60 lit.

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Filed Under: Alligation or Mixture
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15 5866

Q:

Sneha’s weight is 140% of Veena’s weight. Rina’s weight is 90% of Sana’s weight. Sana weighs twice as much as Veena. If Sneha’s weight is x% of Rina’s weight, then x is equal to:

A) 596/9	B) 605/9
C) 645/9	D) 700/9

Answer & Explanation Answer: D) 700/9

Explanation:

Let Veena's weight = 1 kg

Sana's weight = 2 kg

Sneha's weight = 1.4 kg

Rina's weight = 1.8 kg

Now,according to the given data in the question,

$\frac{1.8 x}{100} = 1.4$

x = $\frac{1.4 \times 100}{1.8} = \frac{700}{9} = 77 \frac{7}{9}$ .

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Q:

When the price of rice decrease by 10%, a girl could buy 1 kg more for Rs. 270. Then, the original price of the rice per kg is

A) Rs. 36	B) Rs. 30
C) Rs. 28	D) Rs. 40

Answer & Explanation Answer: B) Rs. 30

Explanation:

From the given data,

When the price of rice is decreased by 10%, the value of Rs. 270 would become

270 x 100/90 = 300

Now, the value 270 becomes 300

And given, the girl could buy 1 kg extra for that value

Change in value = 300 - 270 = Rs. 30

Therefore, 1 kg extra rice she can get for Rs. 30

=> The original price of rice = Rs. 30/kg.

As she gets only 9 kgs for Rs. 270 before 10% discount, now after discount she gets 10 kgs instead of 9 kgs for Rs. 270.

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27 5865

Q:

The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:

A) 625	B) 635
C) 645	D) 655

Answer & Explanation Answer: A) 625

Explanation:

Let the sum be Rs. x. Then

C.I=x[1+4/100)^2-x]=[626/675x-x]

S.I=x^2/25

C.I-S.I=1

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Filed Under: Compound Interest
Exam Prep: Bank Exams
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0 5860

Quantitative Aptitude - Arithmetic Ability Questions

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