Quantitative Aptitude - Arithmetic Ability Questions

17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)

Odd days in 1600 years = 0

Odd days in 300 years = (5 x 3) 1

97 years has 24 leap years + 73 ordinary years.

Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.

Jan. Feb. March April May June

(31 + 28 + 31 + 30 + 31 + 17) = 168 days

168 days = 24 weeks = 0 odd day.

Total number of odd days = (0 + 1 + 2 + 0) = 3.

Given day is Wednesday

hence P=7Q

P+QP-Q=7Q+Q7Q-Q=8Q6Q=43

1523+2323=19-423+19+423  

 The remainder on dividing by 19 will be -423+423= 0.

Suppose the ages of three persons are x, 2x, 3x years respectively 

Hence, age of youngest person = x = 30 years.

If John must be on the committee,we have 11 students remaining,out of which we choose 4. So,11C4

Suppose B joined for x months.

Given profit is divided in the ratio 3:1. Then,

85000×1242500×x=31

 --> x = 8 months.

Let total number of votes enrolled = x
No. of voted cast = 70% of x = 0.7x
Valid votes = 98% of 0.7x
⇒ 60% of total valid votes = 7203 = 60% of 98% of 0.7x
⇒ 0.6 X 0.98 X 0.7x = 7203
⇒ x = 7203 / (0.6 X 0.98 X 0.7)
⇒ x = 17500

Length of train A = 48 x 9 x 5/18 = 120 mts

Length of train B = 48 x 24 x 5/18 - 120

=> 320 - 120 = 200 mts.