6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

If $A = \frac{l o g_{3} (2187)}{5}$ and $B = l o g_{243} (2187)$ , then which one of the following is correct?

A) A	B) A=B
C) A>B	D) can't be determined

Answer & Explanation Answer: B) A=B

Explanation:

Given $A = \frac{\log_{3} (2187)}{5} a n d B = \log_{243} (2187)$

$B = \log_{3^{5}} (2187) = \frac{\log_{3} (2187)}{5}$

=> A

Therefore, A = B

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Filed Under: Logarithms
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7 5716

Q:

A jar can 20 litre milk. From the jar, 4 litres milk was taken out and replaced with an equal quantity of water. If 4 litres of the newly formed mixture is taken out of the can, then what is the final quantity of milk left in the can?

A) 14.5 lit	B) 12.8 lit
C) 11.6 lit	D) 10.46 lit

Answer & Explanation Answer: B) 12.8 lit

Explanation:

This can be solved as

$20 {(1 - \frac{4}{20})}^{2} = 20 {(1 - \frac{1}{5})}^{2} = 20 {(\frac{4}{5})}^{2} = 20 (\frac{16}{25}) = \frac{64}{5} = 12.8$

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Filed Under: Percentage
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11 5712

Q:

Find value of $\frac{\log \sqrt{27} + \log 8 + l o g \sqrt{1000}}{\log 120}$

A) 1/2	B) 3/2
C) 2	D) 2/3

Answer & Explanation Answer: B) 3/2

Explanation:

$= \frac{\log \sqrt{3^{3}} + \log 2^{3} + \log \sqrt{10^{3}}}{\log (10 \times 3 \times 2^{2})}$

$= \frac{\log (3^{3})^{\frac{1}{2}} + \log 2^{3} + \log {(10^{3})}^{\frac{1}{2}}}{\log (10 \times 3 \times 2^{2})}$

$= \frac{\frac{1}{2} \log 3^{3} + 3 \log 2 + \frac{1}{2} \log 10^{3}}{\log 10 + \log 3 + \log 2^{2}}$

$= \frac{\frac{3}{2} (\log 3 + 2 \log 2 + \log 10)}{\log 3 + 2 \log 2 + \log 10}$ = $\frac{3}{2}$

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Filed Under: Logarithms
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27 5711

Q:

A school committee of 5 is to be formed from 12 students.How many committees can be formed if John must be on the committee?

A) 11P4	B) 11C4
C) 11P5	D) 11C5

Answer & Explanation Answer: B) 11C4

Explanation:

If John must be on the committee,we have 11 students remaining,out of which we choose 4. So, $11 C_{4}$

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Filed Under: Permutations and Combinations

0 5701

Q:

Two equal sums were lent, one at the rate of 11% per annum for five years and the other at the rate of 8% per annum for six years, both under simple interest. If the difference in interest accrued in the two cases is Rs 1008. Find the sum?

A) Rs. 14,400	B) Rs. 15,600
C) Rs. 14,850	D) Rs. 15,220

Answer & Explanation Answer: A) Rs. 14,400

Explanation:

Let the required Sum = Rs.S

From the given data,

1008 = [(S x 11 x 5)/100] - [(S x 8 x 6)/100]

=> S = Rs. 14,400.

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Filed Under: Simple Interest
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18 5699

Q:

In a competitive examination, the average marks for the entire examination was 60 marks. If 20% of the applicants scored 85 marks and 25% scored 95 marks. What was the average marks of the remaining applicants in the examination ?

A) 60	B) 52
C) 45	D) 35

Answer & Explanation Answer: D) 35

Explanation:

Let the total applicants be 100

Then, 20% got 85 marks

i.e 20 x 85 = 1700

and 25% got 95 marks

i.e 25 x 95 = 2375

Now, the remaining applicants are 55 and let the average marks scored by them be x.

Therefore, 2375 + 1700 + 55x = $60 \times 100$

6000 - 4075 = 55x

55x=1925

x=35.

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Filed Under: Percentage
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8 5676

Q:

A work which could be finished in 11 days was finished 4 days earlier after 4 more men joined. The number of men employed was ?

A) 7	B) 8
C) 9	D) 10

Answer & Explanation Answer: A) 7

Explanation:

As the work is same
M1D1 = M2D2

Here Let the number of men employed was M
=> 11M = 7(M+4)
=> 11M - 7M = 28
=> M = 7

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Filed Under: Time and Work
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4 5668

Q:

LCD of 12 and 18

A) 36	B) 42
C) 12	D) 6

Answer & Explanation Answer: A) 36

Explanation:

LCD is nothing but Lowest or Least Common Denominator

Here LCD of 12 and 18 means LCD of two fractions with denominators 12 and 18 respectively.

Therefore, LCM of 12 & 18 = 6 x 3 x 2 = 36

How to calculate LCD ::

The lowest common denominator or least common denominator (LCD) is the least common multiple (LCM) of the denominators of a set of fractions.

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Filed Under: HCF and LCM
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27 5658

Quantitative Aptitude - Arithmetic Ability Questions

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