6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area?

A) 25% increase	B) 50% increase
C) 50% decrease	D) 75% decrease

Answer & Explanation Answer: B) 50% increase

Explanation:

Let original length = x and original breadth = y.

Original area = xy.

New length = x/2 and New breadth = 3y.

New area = (x/2 * 3y) = (3/2 )xy

Therefore, Increase % = [(1/2)xy * (1/xy) * 100] % = 50%

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Filed Under: Volume and Surface Area

0 5872

Q:

Sandeep got Rs. 6000 as his share out of the total profit of Rs. 9000 which he and Saketh earned at the end of one year. If Sandeep invested Rs. 20000 for 6 months, whereas Saketh invested his amount for the whole year, the amount invested by Saketh?

A) Rs. 5000	B) Rs. 6200
C) Rs. 8100	D) R. 7600

Answer & Explanation Answer: A) Rs. 5000

Explanation:

Let the amount invested by saketh = RS. p

Now, that of sandeep = 20,000 x 6

saketh = 12 x p

Ratio of their earnings = 120000 : 12p = 6000 : (9000 - 6000)

=> $\frac{120000}{12 p} = \frac{6000}{3000} = > p = Rs . 5000$

Hence, the amount investe by saketh = Rs. p = Rs. 5000.

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Filed Under: Partnership
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13 5864

Q:

$2660 o f \frac{1}{7} o f \frac{1}{2} o f \frac{1}{9.5} o f \frac{1}{2} = ?$

A) 1	B) 10
C) 0.1	D) 100

Answer & Explanation Answer: B) 10

Explanation:

$\frac{1}{7} x \frac{1}{2} x \frac{1}{9.5} x \frac{1}{2} x 2660 = \frac{2660}{266} = 10$

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Filed Under: Simplification
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3 5861

Q:

Maneela, Raghu and Aravind have some jems with each of them. Five times the number of jems with Raghu equals seven times the number of jems with Maneela while five times the number of jems with Maneela equals seven times the number of jems with Aravind. What is the minimum number of jems that can be there with all three of them put together ?

A) 108	B) 107
C) 109	D) 110

Answer & Explanation Answer: C) 109

Explanation:

From given data,

R : M = 5 : 7

M : A = 5 : 7

R : M : A = 25 : 35 : 49

25 + 35 + 49 = 109

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Filed Under: Ratios and Proportions
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15 5859

Q:

In what ratio must a merchant mix two varieties of oils worth Rs. 60/kg and Rs. 65/kg, so that by selling the mixture at Rs. 68.20/kg, he may gain 10% ?

A) 2:3	B) 4:3
C) 3:4	D) 3:2

Answer & Explanation Answer: D) 3:2

Explanation:

Let he mixes the oils in the ratio = x : y

Then, the cost price of the oils = 60x + 65y

Given selling price = Rs. 68.20

=> Selling price = 68.20(x+y)

Given profit = 10% = SP - CP

=> 10/100 (60x + 65y) = 68.20(x+y)-(60x + 65y)

=> 6x + 6.5y = 8.20x + 3.20y

=>2.2x = 3.3y

=> x : y = 3 : 2

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Filed Under: Alligation or Mixture
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17 5853

Q:

Find value of $\frac{\log \sqrt{27} + \log 8 + l o g \sqrt{1000}}{\log 120}$

A) 1/2	B) 3/2
C) 2	D) 2/3

Answer & Explanation Answer: B) 3/2

Explanation:

$= \frac{\log \sqrt{3^{3}} + \log 2^{3} + \log \sqrt{10^{3}}}{\log (10 \times 3 \times 2^{2})}$

$= \frac{\log (3^{3})^{\frac{1}{2}} + \log 2^{3} + \log {(10^{3})}^{\frac{1}{2}}}{\log (10 \times 3 \times 2^{2})}$

$= \frac{\frac{1}{2} \log 3^{3} + 3 \log 2 + \frac{1}{2} \log 10^{3}}{\log 10 + \log 3 + \log 2^{2}}$

$= \frac{\frac{3}{2} (\log 3 + 2 \log 2 + \log 10)}{\log 3 + 2 \log 2 + \log 10}$ = $\frac{3}{2}$

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Filed Under: Logarithms
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27 5852

Q:

A began a business with Rs. 85000. He was joined afterwards by B with Rs. 42,500. For how much perod does B join, if the profits at the end of the year are divided in the ratio of 3:1 ?

A) 8 months	B) 6 months
C) 7 months	D) 9 months

Answer & Explanation Answer: A) 8 months

Explanation:

Suppose B joined for x months.

Given profit is divided in the ratio 3:1. Then,

$\frac{85000 \times 12}{42500 \times x} = \frac{3}{1}$

--> x = 8 months.

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Filed Under: Partnership
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6 5847

Q:

In how many ways can the letters of the word 'MISSISIPPI' be arranged ?

A) 12400	B) 11160
C) 16200	D) 12600

Answer & Explanation Answer: D) 12600

Explanation:

Total number of alphabets = 10

so ways to arrange them = 10!

Then there will be duplicates because 1st S is no different than 2nd S.

we have 4 Is 3 S and 2 Ps

Hence number of arrangements = 10!/4! x 3! x 2! = 12600

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Filed Under: Permutations and Combinations

0 5847

Quantitative Aptitude - Arithmetic Ability Questions

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