Quantitative Aptitude - Arithmetic Ability Questions

Cost of 4 mangoes = Rs. 6 

Cost of 1 mango = Rs. 6/4 = Rs. 1.5

Now, Selling Price of 4 mangoes = Rs. 4

Selling Price of 1 mango = Rs. 4/4 = Rs. 1.0

• We observe that, S.P < C.P

Hence, the shopkeeper incurs a loss.

Required loss% = loss/C.P x 100

Loss = 1.5 - 1 = 0.5

C.P = 1.5

Loss% = (0.5/1.5) x 100

 = (5/15) x 100

 = 1/3 x 100

 = 100/3

 = 33.333%.

Monday + Tuesday + Wednesday = 37 x 3 -----------(1)
Tuesday + Wednesday + Thursday = 34 x 3---------(2)
Thursday = 4/5 of Monday ------------------(3)
subtract eqn (1) from (2) we get,
Thursday - Monday = -9
=> Monday - Thursday = 9.......(4)
From (3) & (4), we get

So,Thursday = 36 C

Px85100=120

=> p = 12000/85 = 141.17 %

Let rate = R% and time = R years.

Then, (1200 x R x R) / 100 = 432

=> R = 6.

M = 10 days

The ratio of efficiency of M & N are 3 : 2

Hence, the time rquired for N alone = 15 days

=> Required time taken t=by both to complete the work = M x N / M + N 

= 10 x 15/ 10 + 15

= 150/25

= 6 days.

Given that to find 15 of 80

=> What % of 80 is 15

Let it be 'p'

=> p% of 80 = 15

=> $$\begin{gathered} p x 80100 = 15 \\ ⇒p = 15 x 10080 \\ ⇒p = 150080 = 18.75 \end{gathered}$$

Therefore, 15 is 18.75% of 80 => 18.75% of 80 = 15

Example::

Now, in the similar way we can find 15% of 80 =?

=> 15x80/100 = p

=> p = 4 x 3 = 12

Therefore, 15% of 80 = 12

3/15 + 4/16 + x/24 = 1

⇒x=1315