Quantitative Aptitude - Arithmetic Ability Questions

On 31st December, 2005 it was Saturday.

Number of Odd days from the year 2006 to the year 2009 = (1+1+2+1)=5 days.

 On 31st december 2009, It was Thursday

Thus, on 1st Jan, 2010 it is Friday.

For this we have to find the LCM of 24, 36 and 30

LCM of 24, 36 and 30 = 360 sec

360/60 min = 6 minutes.

Ans. B.
According to the question ,
Marked Price = 1600 + Cost price - (i)
MP – 500 = 125/100 * CP - (ii)
MP = 5/4 CP + 500 - (ii)
4MP = 5CP + 2000 -(ii)
Solving (i) and (ii)
Cost Price = 4400
Now , the selling price
= 130/100 * 4400
= 5720

Let total amount = Rs. P

Total expenditure = (23 + 33 + 19 + 16)% of P = 91%ofP

Remaining money = (100 - 91)% of P = 9% of P

But given in the question that,

9% of P = 504

9p/100 = 504

=> P = 50400/9

=> P = Rs. 5600

Required money spent on Food & Insurance = 23 + 33 %

= 56% of 5600

= 56 x 5600/100 = 56 x 56 = Rs. 3136

4 persons can be selected from 9 in 9C4 ways =126

Fvaourable events =4C2*5C2 =60

So,required probability = 60/126 = 10/21

Let the required weight be x kg.

Less weight, Less cost (Direct Proportion)

 250 : 200 :: 60 : x   =>    250 x x = (200 x 60)

=>

=> x = 48.

Given in municipality election 54% votes have won by 1080

Let the total number of votes be x.

 54x100 - 46x100 = 1080

8x = 108000

x = 13,500

Therefore, total number of votes = 13,500.

As these three strategies P, Q and R are independent so these will cut cost one after the other.
If initial cost is Rs 100, then
20% cost is cut after initializing strategy P, then cost will remain 80% = 80
further 30% cost is cut after strategy Q, then cost will remain 70% of 80 = 56
further 10% cost is cut after strategy R, then cost will remain 90% of 56 = 50.4

Thus final cost remains 50.4 % of the original cost. Hence net saving is 100 - 50.4 = 49.6 %.