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 Quantitative Aptitude - Arithmetic Ability Questions

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Q:

Solve the following :

 

(-8) [36 / {7 - (-2)}] / (-4){19 - (-3) x (-5)} = ?

A) 4 B) -4
C) -2 D) 2
 
Answer & Explanation Answer: D) 2

Explanation:
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Q:

Suppose 0 < θ < 90, then for every θ 4 sin2 θ + 1 is greater than or equal to ?

 

A) 2 B) 4 sin θ 
C) 4 cos θ  D) 4 tan θ
 
Answer & Explanation Answer: B) 4 sin θ 

Explanation:
We know that,
Arithmetic mean ≥ Geometric mean
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Q:

Which value is closest to [5.168 x 4453 x 3.194 / 67.999 x 4224.017]

 

A) 0.2 B) 0.002
C) 2 D) 0.02
 
Answer & Explanation Answer: A) 0.2

Explanation:
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Q:

Find the next number in the given series ?


3, 7, 6, 5, 9, 3, 12, 1, 15, . . .

A) 2 B) 0
C) 1 D) -1
 
Answer & Explanation Answer: D) -1

Explanation:

3, 7, 6, 5, 9, 3, 12, 1, 15, ... has two different series

1) 3, 6, 9, 12, 15.....

2) 7, 5, 3, 1, .....

-1 is the next number.

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Filed Under: Odd Man Out
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3 62858
Q:

In the given figure, if  QR/XY = 14/9 and PY = 18 cm, then what is the value (in cm) of PQ?

 

 

A) 28 B) 18
C) 21 D) 24
 
Answer & Explanation Answer: A) 28

Explanation:
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Filed Under: Area
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Q:

Directions: What value should come in place of question mark (?) in the following question?

69÷3×0.85+24.5-13.8=?

A) 31.75  B) 30.25 
C) 28.95  D) 35.25 
 
Answer & Explanation Answer: B) 30.25 

Explanation:

= (69x85/3x100) + 10.7

= 30.25.

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Q:

Find compound interest on Rs. 8000 at 15% per annum for 2 years 4 months, compounded annually

A) 2109 B) 3109
C) 4109 D) 6109
 
Answer & Explanation Answer: B) 3109

Explanation:

Time = 2 years 4 months = 2(4/12) years = 2(1/3) years.
Amount = Rs'. [8000 X (1+(15/100))^2 X (1+((1/3)*15)/100)]
=Rs. [8000 * (23/20) * (23/20) * (21/20)]
= Rs. 11109. .
:. C.I. = Rs. (11109 - 8000) = Rs. 3109.

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Q:

The speed of a car increases by 2 kms after every one hour. If the distance travelling in the first one hour was 35 kms. what was the total distance travelled in 12 hours?

A) 456 kms B) 482 kms
C) 552 kms D) 556 kms
 
Answer & Explanation Answer: C) 552 kms

Explanation:

Total distance travelled in 12 hours    =(35+37+39+.....upto 12 terms)
This is an A.P with first term, a=35, number of terms,
n= 12,d=2.
Required distance    = 12/2[2 x 35+{12-1) x 2]
=6(70+23)
= 552 kms.

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