Quantitative Aptitude - Arithmetic Ability Questions

Q:

Find the odd man out 1 4 9 16 22 36?

A) 9 B) 16
C) 22 D) 36
 
Answer & Explanation Answer: C) 22

Explanation:

In the given series 1 4 9 16 22 36

1 = 1 x 1 

4 = 2 x 2

9 = 3 x 3

16 = 4 x 4

25 = 5 x 5 (Not 22)

36 = 6 x 6

 

Hence, the odd man in the series is 22.

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Q:

A constructor estimates that 4 people can paint Mr. Karthik's house in 6 days. If he uses 5 people instead of 4, how long will they take to complete the job ?

A) 3 days B) 26/3 days
C) 13/4 days D) 24/5 days
 
Answer & Explanation Answer: D) 24/5 days

Explanation:

we know that m1 x d1 = m2 x d2
=> 4 x 6 = 5 x d
where d = no. of days taken by 5 men to paint
d = 24/5 days.

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Filed Under: Time and Work
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Q:

Two parallel chords on the same side of the centre of a circle are 5 cm apart. If the chords are 20 and 28 cm long, what is the radius of the circle? 

A) 14.69 cm B) 15.69 cm
C) 18.65 cm D) 16.42 cm
 
Answer & Explanation Answer: B) 15.69 cm

Explanation:

circle11487663359.jpg image

Draw the two chords as shown in the figure. Let O be the center of the circle. Draw OC
perpendicular to both chords. That divides the two chords in half.
So CD = 10 and AB = 14. Draw radii OA and OD, both equal to radius r.
We are given that BC = 5, the distance between the two chords. Let
OB = x.

We use the Pythagorean theorem on right triangle ABO

AO² = AB² + OB²
r² = 14² + x²

We use the Pythagorean theorem on right triangle DCO

DO² = CD² + OC²

We see that OC = OB+BC = x+5, so

r² = 10² + (x+5)²

So we have a system of two equations:

r² = 14² + x²
r² = 10² + (x+5)²

Since both left sides equal r², set the right sides
equal to each other.

14² + x² = 10² + (x+5)²
196 + x² = 100 + x² + 10x + 25
196 = 125 + 10x
71 = 10x
7.1 = x

r² = 14² + x²
r² = 196 + (7.1)²
r² = 196 + 50.41
r² = 246.41
r = √246.41
r = 15.69745202 cm

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Filed Under: Simplification
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4 4376
Q:

The number of sequences in which 4 players can sing a song, so that the youngest player may not be the last is ?

A) 2580 B) 3687
C) 4320 D) 5460
 
Answer & Explanation Answer: C) 4320

Explanation:

Let 'Y' be the youngest player.

The last song can be sung by any of the remaining 3 players. The first 3 players can sing the song in (3!) ways.

The required number of ways = 3(3!) = 4320.

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Filed Under: Permutations and Combinations
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Q:

By investing Rs. 1620 in 8% stock, Michael earns Rs. 135. The stock is then quoted at ?

A) Rs. 145 B) Rs. 245.1
C) Rs. 96 D) Rs. 75
 
Answer & Explanation Answer: C) Rs. 96

Explanation:

Michel earns Rs. 135 by investing Rs. 1620
To earn Rs. 8 how much he have to invest...?

= (8 x 1620)/135 = Rs. 96

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Filed Under: Stocks and Shares
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Q:

K and L start a business jointly. L invests Rs.16000 for 8 months and L remains in the business for 4 months. Out of the total profit B claims 2/7th share. How much money is contributed by B  ?

A) Rs. 9040 B) Rs. 10,400
C) Rs. 12,800 D) Rs. 6350
 
Answer & Explanation Answer: C) Rs. 12,800

Explanation:

16x8 : Px4 = 5:2

P = 12.8 => Rs.12,800

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Filed Under: Partnership
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4 4372
Q:

Manisha went to shop with certain amount, with which she can buy 50 Chacobar or 40 Fivestar. She uses 10% amount for petrol and out of the remaining balance, she purchases 20 Fivestar and some Chacobar. Find the number of Chacobar she can buy?

A) 20 B) 24
C) 26 D) 28
 
Answer & Explanation Answer: A) 20

Explanation:

Let the total amount be 200 {L.C.M of 40 and 50}

Chacobar C.P. = 200/50 = 4

Fivestar C.P = 200/40 = 5

Remaining Money after petrol = [200 - 200×10%] = 180

Remaining money after buying fivestars = [180 - 20×5] = 80

So number of Chacobar she can buy = 80/4 = 20

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Q:

Two cards are drawn at random from a well - shuffled pack of 52 cards. what is the probability that either both are red or both are queens?

A) 17/112 B) 55/221
C) 55/121 D) 33/221
 
Answer & Explanation Answer: B) 55/221

Explanation:

n(S) = C252 = 1326

 

 Let  A = event of getting both red cards

 

and B = event of getting both queens

 

then AB = event of getting two red queens

 

n(A) = C226 = 325,   n(B) = C24 = 6

 

 n(AB)=C22=1

 

  PA=3251326, PB = 61326

 

 PAB=11326

 

P ( both red or both queens) = PAB

 

PA+PB-PAB=3251326+1221-11326=55221

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