Quantitative Aptitude - Arithmetic Ability Questions

Total numbers in die=6

P(multiple of 2)=1/2

P(multiple of 5)=1/6

P(multiple of 2 or 5)=2/3

Rate of rice of quantity 280 kg = Rs. 15.60/kg

Rate of rice of quantity 120 kg = Rs. 14.40/kg

He want to earn a profit of Rs. 10.45/kg

Rate of Mix to sell to get profit of 10.45 =  

$$\begin{gathered} 280 x 15.60 + 120 x 14.40280 + 120 + 10.45 \\ 4368 + 1728400 + 10.45 \\ => 15.24 + 10.45 \\ = 25.69 \end{gathered}$$

For exampe if it is 12:45 AM, then after 8 hours the time is 

12 hrs 45 min + 8 hrs = 8 : 45 PM in the night on the same day. 

Mass of zinc ore = 8000 kg

Mass of metal = 60% of 8000 = 4800 kg

Mass of silver in metal = 3/4 x 4800/100 = 36 kg

Mass of zinc = 4800 - 36 = 4764 kg.

If a number ends with 5, 0 then the number will be divisible by 5
Here only 5 is present, end place will be fixed by 5 so, 

Let the cost price of A as well as B is 100 Rs.
Then, ATQ:
Selling Price of A = 100+40 = 140
And Selling Price of B = 140 - (140*0.2) = 140 - 28 = 112
Total selling price = 140+112 = 252 Rs.
Total Cost price = Rs. 200
So by taking cost price = 100 Rs.
Total profit = 52 Rs.
Total profit will be Rs. 156 when cost price = (100/52)*156 = Rs. 300.

a. P's investment = (80000 x 6 + 60000 x 6) = 840000 for 1 month.

b & c. Q's investment = 80% of Rs. 60000 for 8 months.

= Rs.(48000 x 8) for 1 month = 384000 for 1 month

P : Q = 840000 : 384000 = 35 : 16.

But, the total profit is not given, so data is inadequate.

Let present ages of Sushanth = w, Krish = x, Rishi = y and Rohit = z , then
w + x + y = 43 x 3 = 129 ---(i) and
w + y + z = 49 x 3 = 147 ---(ii)
Subtracting (i) from (ii), (w+y+z) - (w+x+y) = 147 - 129 , z - x = 18 ---(iii)
Given Rohit's age=z=54, so from (iii), x = 54 - 18 = 36.
Therefore, Krish age is 36 years.