6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

If $x = 2 + 2^{\frac{2}{3}} + 2^{\frac{1}{3}}$ then find the value of $x^{3} - 6 x^{2} + 6 x$ ?

A) 1	B) 2
C) 3	D) 4

Answer & Explanation Answer: B) 2

Explanation:

Given that $x = 2 + 2^{\frac{2}{3}} + 2^{\frac{1}{3}}$

So x - 2 = $2^{\frac{2}{3}} + 2^{\frac{1}{3}}$

Now cubing on both sides, we get

=> $x^{3} - 8 - 6 x^{2} + 12 x = 4 + 2 + 6 (x - 2)$

Therefore, $x^{3} - 6 x^{2} + 6 x = - 6 + 8 = 2$

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Filed Under: Square Roots and Cube Roots
Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
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Q:

The sum of the two digits of a number is 8. If the number is subtracted from the number obtained by reversing its digits, the result is 54. Find the number ?

A) 28	B) 19
C) 37	D) 17

Answer & Explanation Answer: D) 17

Explanation:

Any two digit number can be written as (10P + Q), where P is the digit in the tens place and Q is the digit in the units place.
P + Q = 8 ----- (1)
(10Q + P) - (10P + Q) = 54
9(Q - P) = 54
(Q - P) = 6 ----- (2)
Solve (1) and (2) P = 1 and Q = 7
The required number is = 17

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Filed Under: Problems on Numbers
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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1 2748

Q:

You deposit $600 into a 6 month certificate of deposit. After 6 months the balance is $618. Find the simple annual interest rate.

A) 5%	B) 4%
C) 6%	D) 7%

Answer & Explanation Answer: C) 6%

Explanation:

I=prt

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Filed Under: Simple Interest
Exam Prep: Bank Exams
Job Role: Bank PO

0 2747

Q:

The true discount on Rs.1600 due to after a certain of 5% per annum is Rs.160. The time after which it is due is

A) 27months	B) 23months
C) 20months	D) 12months

Answer & Explanation Answer: A) 27months

Explanation:

P.W. = Rs. (1600 - 160) = Rs. 1440
∴ S.I. on Rs.1440 at 5% is Rs. 160.
∴ Time = [100 * 160 / 1440 * 5] = 20/9 years = [20/9 * 12] months = 27 months.

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Filed Under: True Discount

0 2744

Q:

What will be the ratio of simple interest earned by certain amount at the same rate of interestfor 4 years and 6 years ?

A) 1:2	B) 2:1
C) 2:3	D) 3:2

Answer & Explanation Answer: C) 2:3

Explanation:

Let p be the principle amount

And R% be the rate of interest

Then, required ratio = $(\frac{\frac{P \times 4 \times R}{100}}{\frac{P \times 6 \times R}{100}})$

$\Rightarrow \frac{4 P R}{6 P R}$ = 2:3

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Filed Under: Simple Interest
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2 2740

Q:

A, B and C together can finish a task in 12 days. A is twice as productive as B and C alone can do the task in 36 days. In how many days can A and B do the task if C goes on leave?

A) 10	B) 20
C) 15	D) 18

Answer & Explanation Answer: D) 18

Explanation:

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Filed Under: Time and Work
Exam Prep: Bank Exams

3 2738

Q:

Express 3/8 and 1/10 as a Decimals?

A) 1.375 & 1	B) 0.375 & 1
C) 13.75 & 1.1	D) 0.375 & 0.1

Answer & Explanation Answer: D) 0.375 & 0.1

Explanation:

3/8 as a Decimal :

In this we should convert the denominator into 10, 100, 1000, 10000, 100000,... to make it simple.

Now to make 8 into 1000, we multiply numerator and denominator with 125

=> $\frac{3 x 125}{8 x 125} = \frac{375}{1000} = 0.375$

1/10 as a Decimal :

1 divided into 10 parts of each 0.1.

Therefore, 3/8 = 0.375 and 1/10 = 0.1 in decimals.

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Filed Under: Decimal Fractions
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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3 2737

Q:

Anmol soldtwo items for Rs 1000 each. On one, he gained 10% and on other, he lost 10%. How much did he gain or lose in the whole transaction?

A) profit,0.95%	B) loss,1%
C) profit,10%	D) loss,10%

Answer & Explanation Answer: B) loss,1%

Explanation:

Let the two item be A and B.

Cost price of A be x and cost price of B be y.

A sold for Rs 1000 on 10 % gain = 1.1x =1000

x= 1000/1.1 = 909.09

B sold for Rs. 1000 on 10% loss = 0.9y =1000y= 1000/0.9 = 1111.11

Total cost price of A and B = 2020.20

Selling price of A and B = 2000

Loss % = (2020.20 –2000)/2000 X 100

= 1.01 % loss

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Filed Under: Profit and Loss

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Quantitative Aptitude - Arithmetic Ability Questions

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