Quantitative Aptitude - Arithmetic Ability Questions

Given that three athletes can complete one round around a circular field in 16, 24 and 36 min respectively.

Now, required time after which they met for the first time = LCM of (16, 24 & 36) min

Now, LCM of 16, 24, 36 = 144 minutes = 2 hrs 24 min.

Price of 1kg fresh cashew = Rs.120
Therefore, price of 10kg = Rs.120 x 10 = Rs.1200

10% of 10kg which eaten by rodents = 10 x 10/100 = 1kg.

So, End of Year he had 10kg - 1kg = 9kg

So, he sells that 9kg with Rs.20 per kg profit = 9 x 140 = 1260.

He buy 10kg wooden box with cashew for Rs.1200 and sell that for Rs. 1260

So, profit = 1260 - 1200 = Rs.60 more money he get.

Annual salary of Arun = 7,68,000 Rs.
Monthly salary = 7,68,000/12 = Rs. 64,000
Spending on children = Rs. 12,000
Rest = 52,000
1/13th of the rest = 52,000/13 = Rs. 4,000 is spent on food.
Rs. 8,000 is spent in mutual funds.
Monthly savings = 64,000 - (12,000+4,000+8,000) = Rs. 40,000.

Cost of Rs. 100 stock   = Rs. (100-15)

Cost of Rs. 6400 stock = Rs.85100*6400 = Rs. 5440.

As water costs free, water sold at cost price of milk gives the profit.

Required profit % = 5/20 x 100 = 5 x 5 = 25%.

P(heart cards)=13/52

P(diamond cards)=13/52

P(heart or diamond)=13/52+13/52=1/2

For an income of Rs. 756, investment = Rs. 9000. 

For an income of Rs.212,  investment =Rs.9000756×212 = Rs. 125.

For a Rs. 100 stock, investment = Rs. 125.

Market value of Rs. 100 stock = Rs.125-14= Rs. 124.75

Here to say which fraction is greater from the given options, the fraction with greater numerator with same denominator or smaller denominator with same numerator.

To find the greater fraction, among the given options, make the denominators same for the options by finding the LCM of all the denominators.

7/12, 9/16, 13/20, 32/80

Now, LCM of 12, 16, 20, 80 = 240.

Then,

140/240, 135/240, 156/240, 96/240

Here 

$$\begin{gathered} 156240 > 140240 > 135240 > 96240 \\ => 1320 > 712 > 916 > 3280 \end{gathered}$$

Hence, largest fraction = 13/20.