6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Find the cost of Rs. 6400, 10% stock at 15 discount?

A) 2000	B) 5440
C) 6000	D) 5140

Answer & Explanation Answer: B) 5440

Explanation:

Cost of Rs. 100 stock = Rs. (100-15)

Cost of Rs. 6400 stock = $R s . \frac{85}{100} * 6400$ = Rs. 5440.

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Filed Under: Stocks and Shares

1 3948

Q:

In a city of engineers of 4800, the number of female engineers are 3/8th of them. The number of female engineers is what percentage of the number of male engineers?

A) 76	B) 60
C) 56	D) 52

Answer & Explanation Answer: B) 60

Explanation:

Total engineers = 4800

Number of female engineers = 3/8 x 4800 = 1800

Then, number of male engineers = 4800 - 1800 = 3000

Now, required is female engineers is what percentage of the number of male engineers

=> 1800 is what % of 3000

=> p x 3000/100 = 1800

=> 30p = 1800

p = 60%

Hence, female engineers is 60 percentage of the number of male engineers.

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Filed Under: Percentage
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6 3946

Q:

The difference between compound interest and simple interest on an amount of Rs. 15,000 for 2 years is Rs. 96. What is the rate of interest per annum?

A) 8	B) 10
C) 12	D) 14

Answer & Explanation Answer: A) 8

Explanation:

[15000*(1+r/100)2-15000]-(15000*r*2)/100=96

Rate=8%

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

0 3944

Q:

In a hostel the rent per room is increased by 20%. If number of rooms in the hostel is also increased by 20% and the hostel is always full, then what is the percentage change in the total collection at the cash counter?

A) 30%	B) 40%
C) 44%	D) 48%

Answer & Explanation Answer: C) 44%

Explanation:

Let initial rent be rs 10

And initial rooms be 10

So initial collection = 10*10 = Rs 100

Now new rent = 10 + 20% of 10 = 12

New no of rooms = 10 + 20% of 10 = 12

So new collection = 12*12 = 144

% change in collection = (144-100)/100*100 = 44%

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Filed Under: Percentage
Exam Prep: Bank Exams

4 3940

Q:

The difference between Simple Interest and Compound Interest at the rate of 12% on the same amount for 3 years is Rs. 112.32. What is the principal amount if interest is compounded annually?

A) Rs. 25000	B) Rs. 2500
C) Rs. 50000	D) Rs. 5000

Answer & Explanation Answer: B) Rs. 2500

Explanation:

Let the principal amount be Rs. x
Calculating SI:
SI for 1 year at 12% rate is Rs (12/100)*x. For 3 years it will be Rs (36/100)*x ------ (1)
Calculating CI:
For 1st year, Interest = (12/100)*x
For 2nd year, interest = (12/100)*x + (12/100)*x + (144/10000)*x
For 3rd year, interest = (12/100)*x + (12/100)*x + (12/100)*x + (144/10000)*x + (144/10000)*x + (1728/1000000)*x. ------ (2)
Subtracting equation 2 and 1 and solving further,
312*144*x/1000000 = 112.32
X = Rs 2500.
Alternative way: Using formula for Difference
between CI and SI for 3 years

we can also use the above formula to find the value of P.

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Filed Under: Simple Interest
Exam Prep: AIEEE , Bank Exams , GATE

3 3930

Q:

Find the compound interest on Rs. 2680 at 8% per annum for 2 years ?

A) Rs. 664.21	B) Rs. 548.68
C) Rs. 445.95	D) Rs. 692.57

Answer & Explanation Answer: C) Rs. 445.95

Explanation:

We know Compound Interest = C.I. = P1+r100t - 1

Here P = 2680, r = 8 and t = 2

C.I. = 26801 + 81002-1= 268027252-12= 26802725+12725-1= 2680 5225×225

= (2680 x 52 x 2)/625

= 445.95

Compound Interest = Rs. 445.95

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Filed Under: Compound Interest
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12 3928

Q:

The B.D. and T.D. on a certain sum is Rs.200 and Rs.100 respectively. Find out the sum.

A) Rs. 400	B) Rs. 300
C) Rs. 100	D) Rs. 200

Answer & Explanation Answer: D) Rs. 200

Explanation:

$F = \frac{B D \times T D}{B D - T D} = \frac{200 \times 100}{200 - 100} = \frac{200 \times 100}{100} = R s . 200$

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Filed Under: Banker's Discount

1 3927

Q:

A bike runs at the speed of 35 km/h when not serviced and runs at 55 km/h, when serviced. After servicing the bike covers a certain distance in 5 h. How much approximate time will the bike take to cover the same distance when not serviced?

A) 8 hrs	B) 7.5 hrs
C) 7 hrs	D) 6.5 hrs

Answer & Explanation Answer: A) 8 hrs

Explanation:

Given speed of the bike after servicing = 55 kmph

Time taken for travelling some distance at 55 kmph = 5 hrs

Then,

Distance = Speed x Time = 55 x 5 = 275 kms.

Now,

Speed of the bike before servicing = 35 kmph

Distance = 275 kms

Now, Time = Distance/Speed = 275/35 = 7.85 hrs =~ 8 hrs.

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Filed Under: Time and Distance
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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9 3927

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