6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Consider a regular hexagon ABCDEF. Two towers are situated at B and C. The angle of elevation from A to the top of the tower at B is 30 deg, and the angle of elevation to the top of the tower at C is 45 deg. What is the ratio of the height of towers at B and C?

A) 1:√3	B) 1:3
C) 1:2	D) 1:2√3

Answer & Explanation Answer: B) 1:3

Explanation:

Let the side of regular hexagon be ‘a’

Let height of the tower 1 be h1 and tower 2 be h2

Height of tower 1 = h1 = (distance between A and B)* (tan 30o)= a.1/√3

Distance between A and C = 2*√3.a/2= √3a

Height of tower 2 = h2 = (distance between A and C)* (tan 45o) = √3a.1 = √3a

Ratio of height of towers at B and C respectively =a/√3/√3a = 1/3.

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Filed Under: Simplification
Exam Prep: Bank Exams

3 3669

Q:

How many prime numbers exist in $6^{5} \times 35^{9} \times 11^{3}$ ?

A) 29	B) 31
C) 33	D) 27

Answer & Explanation Answer: B) 31

Explanation:

Given $6^{5} \times 35^{9} \times 11^{3}$

$\Rightarrow {(2 \times 3)}^{5} \times {(5 \times 7)}^{9} \times 11^{3}$

$\Rightarrow 2^{5} \times 3^{5} \times 5^{9} \times 7^{9} \times 11^{3}$

Thus, there are (5 + 5 + 9 + 9 + 3)= 31 prime numbers.

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Filed Under: Numbers
Exam Prep: CAT
Job Role: Bank PO

5 3667

Q:

Twenty percent of Karthik’s monthly salary is equal to thirty two percent of Nikitha’s monthly salary. Vipin’s monthly salary is four fifth that of Nikitha’s monthly salary. If Vipin’s annual salary is Rs. 3.84 lakhs, what is Karthik’s monthly salary?

A) 32,000	B) 64,000
C) 40,000	D) 52,000

Answer & Explanation Answer: B) 64,000

Explanation:

From the given data,

20% of K = 32% of N

V = 4/5 N

Given Vipin's salary = 3.84 lpa = 3.84/12 = 32,000 per month

Now, N = 5/4 x 32000 = 40000

Now K = 32/20 x 40000 = 64000

Hence, karthik's monthly salary = Rs. 64000.

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Filed Under: Percentage
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10 3665

Q:

A, B and C together can finish a task in 12 days. A is twice as productive as B and C alone can do the task in 36 days. In how many days can A and B do the task if C goes on leave?

A) 10	B) 20
C) 15	D) 18

Answer & Explanation Answer: D) 18

Explanation:

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Filed Under: Time and Work
Exam Prep: Bank Exams

3 3659

Q:

A dealer sells two machines at Rs 12000 each. On one it gains 32% and on the other it looses 32%. What is its profit/loss percentage in the whole transaction?

A) No gain and no loss	B) 1% loss
C) 18% profit	D) 10.24% loss

Answer & Explanation Answer: D) 10.24% loss

Explanation:

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Filed Under: Profit and Loss
Exam Prep: Bank Exams

3 3658

Q:

Aarav's birthday is on Sunday, 12th March . On what day of the week will be Madhup's Birthday in the same year if Madhup was born on 10th August?

A) Thursday	B) Wednesday
C) Friday	D) Saturday

Answer & Explanation Answer: A) Thursday

Explanation:

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Filed Under: Calendar
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20 3648

Q:

In the given number series which follows the definite rules then find out the value of (M, N, O, and P) in second number series.

7 18 42 94 204

4 M N O P

What value will come in place of P?

A) 179	B) 184
C) 164	D) 156

Answer & Explanation Answer: D) 156

Explanation:

Here the given series 7 18 42 94 204 follows a pattern that,

7

7 ×2+4 = 18

18 ×2+6 = 42

42 ×2+10 = 94

94 ×2+16 = 204

Similarly,

4

4 ×2+4 = 12

12 ×2+6 = 30

30 ×2+10 = 70

70 ×2+16 = 156

Hence, the value of P = 156.

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Filed Under: Odd Man Out
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8 3646

Q:

The difference between Simple Interest and Compound Interest at the rate of 12% on the same amount for 3 years is Rs. 112.32. What is the principal amount if interest is compounded annually?

A) Rs. 25000	B) Rs. 2500
C) Rs. 50000	D) Rs. 5000

Answer & Explanation Answer: B) Rs. 2500

Explanation:

Let the principal amount be Rs. x
Calculating SI:
SI for 1 year at 12% rate is Rs (12/100)*x. For 3 years it will be Rs (36/100)*x ------ (1)
Calculating CI:
For 1st year, Interest = (12/100)*x
For 2nd year, interest = (12/100)*x + (12/100)*x + (144/10000)*x
For 3rd year, interest = (12/100)*x + (12/100)*x + (12/100)*x + (144/10000)*x + (144/10000)*x + (1728/1000000)*x. ------ (2)
Subtracting equation 2 and 1 and solving further,
312*144*x/1000000 = 112.32
X = Rs 2500.
Alternative way: Using formula for Difference
between CI and SI for 3 years

Quantitative Aptitude - Arithmetic Ability Questions

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