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 Quantitative Aptitude - Arithmetic Ability Questions

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Q:

A man’s average monthly expenditure for the first four months of the year was Rs. 231.25. For the next five months, the average monthly expenditure was Rs. 22.75 more than what it was during the first four months. If the person spent Rs. 605 in all during the remaining three months of the year, find what percentage of his annual income of Rs. 3500 did he save in the year?

A) 10% B) 15%
C) 20% D) 25%
 
Answer & Explanation Answer: C) 20%

Explanation:

A man's average monthly expenditure for the first four months of the year = Rs.231.25.
For four month = 231.25 * 4 = Rs. 925
For next five month he spend = 231.25 + 22.75 for one month.
In five month he spend = (231.25 + 22.75) X 5 = 1270
If the person spent Rs. 605 in all during the remaining three months of the year,
Total expense = 925+1270+605= 2800
Saving = 3500-2800 = 700
% saving = 700/3500 * 100 = 20%

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Filed Under: Percentage
Exam Prep: Bank Exams

1 3897
Q:

In an election between two candidates, the winning candidate got 70% of the valid votes and won by a majority of 9000 votes. If out of total votes polled 90% votes are valid, then what is the total number of votes polled?

 

A) 30000 B)  25000
C) 22500 D) 27000
 
Answer & Explanation Answer: B)  25000

Explanation:
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Filed Under: Percentage
Exam Prep: Bank Exams

29 3893
Q:

Anmol soldtwo items for Rs 1000 each. On one, he gained 10% and on other, he lost 10%. How much did he gain or lose in the whole transaction?

A) profit,0.95% B) loss,1%
C) profit,10% D) loss,10%
 
Answer & Explanation Answer: B) loss,1%

Explanation:

Let the two item be A and B.

Cost price of A be x and cost price of B be y.

A sold for Rs 1000 on 10 % gain = 1.1x =1000

x= 1000/1.1 = 909.09

B sold for Rs. 1000 on 10% loss = 0.9y =1000y= 1000/0.9 = 1111.11

Total cost price of A and B = 2020.20

Selling price of A and B = 2000

Loss % = (2020.20 –2000)/2000 X 100

= 1.01 % loss

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Filed Under: Profit and Loss

3 3890
Q:

If there is a total of 104 weekly instalments and a third deposit, find the interest rate

A) 2.82 B) 3.82
C) 4.82 D) 5.82
 
Answer & Explanation Answer: C) 4.82

Explanation:

R = (100 x I)/( P x T)

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Filed Under: Simple Interest
Exam Prep: Bank Exams
Job Role: Bank PO

0 3890
Q:

If length of a rectangle is decreased by 6 cm we get a square and the area of square formed is 252 cm2 less than the area of square formed when breadth of the original rectangle is increased by 6 cm. Find the perimeter of the rectangle.

A) 66 cm B) 88 cm
C) 80 cm D) 72 cm
 
Answer & Explanation Answer:

Explanation:

Let length and breadth of rectangle be L cm
and B cm respectively So, ATQ
Area1= (L-6)×B
But this is square, so L-6=B
Area1= (L-6) × (L-6)
Case 2, Area2= L × (B+6),
L=B+6
So, Area2= L × L,
Given, Area2-Area1= 252(L)2-(L-6)2=252
Solving this, L= 24
B= 18
Perimeter= 2(L+B)= 2(24+18)= 84 cm

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams , GATE

3 3884
Q:

A certain sum is invested for 2 years in scheme M at 20% p.a. compound interest (compounded annually), Same sum is also invested for the same period in scheme N at k% p.a. simple interest. The interest earned from scheme M is twice of that earned from scheme N. What is the value of k?

A) 7 B) 11
C) 9 D) 13
 
Answer & Explanation Answer: B) 11

Explanation:

Interest earned in scheme M =   

P1 + 201002  - 1  = 11P25

Interest earned in scheme N =  

P x k x 2100 = Pk50

 

Now, from the given data,

 

11P25 = 2 x Pk50

k = 11

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Filed Under: Compound Interest
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

20 3882
Q:

Agra and Delhi are 160 km apart. A train leaves Agra for Delhi and at the same time another train leaves Delhi for Agra. Both the trains meet 5 hrs after they start moving. If the train travelling from Agra to Delhi travels 6 km/hr faster than the other train, find the speed of the faster train? 

A) 19 kmph B) 13 kmph
C) 7 kmph D) 9 kmph
 
Answer & Explanation Answer: A) 19 kmph

Explanation:

Let the speed of the slower train = p kmph

ATQ,

Speed of the faster train = (p + 6) kmph

Then,

(p + p + 6) x 5 = 160

10p + 30 = 160

10p = 130

p = 13 kmph

Then, speed of the faster train = p + 6 = 13 + 6 = 19 kmph.

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Filed Under: Problems on Trains
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

8 3877
Q:

A 6% stock yields 8%. The market value of the stock is:

A) 70 B) 76
C) 75 D) 80
 
Answer & Explanation Answer: C) 75

Explanation:

For an income of Rs. 8, investment = Rs. 100.

 

For an income of Rs. 6, investment = Rs.1008*6= Rs. 75.

 

Market value of Rs. 100 stock = Rs. 75.

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Filed Under: Stocks and Shares

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