Quantitative Aptitude - Arithmetic Ability Questions

Let the cost price of the bottle = Rs. 100

Selling price of the bottle = Rs. 100 - Rs. 9 = Rs. 91

Then, from the given data,

=> 112 (1/2) - 91 = 15

=> 21 (1/2) = 15

=> 43 = 15

Then 100 = ?

1500/43 = 34.885 =~ 35

Hence, the cost price of the bottle = Rs. 35

Here  18 in decimal means 8th part in 1.

We know that 110 = 0.1

Then,   18 = ?

=> $$\begin{gathered} ? = 18 x 0.1110 \\ = 0.1 x 108 \\ = 0.54 \\ 18= 0.125 \end{gathered}$$

Two digit numbers: The two digits can be 2 and 9: Two possibilities 29 and 92.

Three-digit numbers: The three digits can be 1, 2 and 9 => 3! Or 6 possibilities.

We cannot have three digits as (3, 3, 2) as the digits have to be distinct.

We cannot have numbers with 4 digits or more without repeating the digits.

So, there are totally 8 numbers.

In circumcstances word there are 3C's, 2S's, I, U,R, T, A, N, E

Total = 13 letters

But last letter must be N

Hence, available places = 12

In that odd places = 1, 3, 5, 7, 9, 11

Owvels = 4

This can be done in 6P4 ways 

Remaining 7 letters can be arranged in 7!/3! x 2! ways

Hence, total number of ways = 6P4 x 7!/3! x 2! = 360 x 5040/12 = 1,51,200 ways.