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 Quantitative Aptitude - Arithmetic Ability Questions

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Q:

K men agree to donate a gift of Rs. L to trust. If three men drop out how much more will each have to contribute towards the purchase of the gift ?

A) L / (k-3) B) k / (L-3)
C) 2K / 3L-K D) 3L / K(K-3)
 
Answer & Explanation Answer: D) 3L / K(K-3)

Explanation:

Intial contribution = L/K
After 3 men drop, then contribution =L/K-3
The amount more to pay in contribution = LK-3 - LK

 

= 3LK(K-3)

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Q:

15% of 32 is

A) 3.6 B) 4.8
C) 5.2 D) 5.8
 
Answer & Explanation Answer: B) 4.8

Explanation:

15% of 32 is 

15 x 32/100 = 4.8.

 

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Q:

Weights of two friends A and B are in the ratio of 7 : 8. A’s weight increases by 10% and the total weight of A and B increase by 20%. What is the percentageincrease in the B’s weight?

A) 28.75 B) 11.55
C) 32.85 D) 24.25
 
Answer & Explanation Answer: A) 28.75

Explanation:
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Q:

What will be the acute angle between the hour-hand and the minute-hand at 4:37 p.m.?

A) 18.5° B) 83.5°
C) 18° D) 6.5°
 
Answer & Explanation Answer: B) 83.5°

Explanation:
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Q:

A and B started a partnership business investing in the ratio of 3 : 8. C joined them after 4 months with an amount equal to 3/4th of B. What was their profit (in Rs) at the end of the year if C got Rs 24,000 as his share?

A) 120000 B) 150000
C) 90000 D) 180000
 
Answer & Explanation Answer: C) 90000

Explanation:
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Q:

A student's average marks in five subjects is 82. If the average marks of first two subject is 86.5 and the average marks of last two subjects is 84. Find the marks of third subject?

A) 69 B) 67
C) 71 D) 73
 
Answer & Explanation Answer: A) 69

Explanation:

The total marks of all 5 subjects = 82 x 5 = 410

Total marks of 1st two subjects = 86.5 x 2 = 173

Total marks of last two subjects = 84 x 2 = 168

Now, marks in 3rd subject = 410 - (173 + 168) = 410 - 341 = 69.

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Q:

The ratio of present ages of R and S is 11:17. Before 11 years the ratio of their ages was 11:20. What is R's present age (in years)?

A) 51 B) 33
C) 22 D) 40
 
Answer & Explanation Answer: B) 33

Explanation:
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Q:

In a race of 200 m, A can beat B by 31 m and C by 18 m. In a race of 350 m, C will beat B by ?

A) 25 m B) 21 m
C) 22 m D) 19 m
 
Answer & Explanation Answer: A) 25 m

Explanation:

A:B = 200 : 169
A:C = 200 : 182
 CB = CA×AB 

 

182200×200169

 

=> 182:169

 

When C covers 182 m , B Covers 169 m
When C covers 350 m , B Covers 169182×350
=> 325 m

 

 

 

So C beats B by (350 - 325) = 25 m.

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Filed Under: Time and Distance
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