Quantitative Aptitude - Arithmetic Ability Questions

Q:

The difference between two numbers is 3355. When the larger number is divided by the smaller one, the quotient is 6 and the remainder is 15. The smaller number and larger number respectively ?

A) 546, 3901 B) 415, 3770
C) 668, 4023 D) 404, 3759
 
Answer & Explanation Answer: C) 668, 4023

Explanation:

Let the smaller number be k.
Then, larger number = (3355 + k)
Therefore 3355 + k = (6k + 15)
‹=› 5k = 3340
‹=› k = 668.

Therefore, the smaller number k = 668 and now the larger number = 3355+668 = 4023.

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4 2787
Q:

Calculate the amount on Rs. 1875 for 2 year at 4% per annum, compounded yearly.

A) Rs. 676 B) Rs. 776
C) Rs. 1778 D) Rs. 2028
 
Answer & Explanation Answer: D) Rs. 2028

Explanation:

Amount = P(1 + r/100)^t
Amount = 1875(1 + 4/100)^2
Amount = 1875(104/100)(104/100)
Amount = 2028

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Filed Under: Compound Interest
Exam Prep: Bank Exams

9 2784
Q:

In how many different ways can the letters of the word 'HAPPYHOLI' be arranged?

A) 89,972 B) 90,720
C) 72,000 D) 81,000
 
Answer & Explanation Answer: B) 90,720

Explanation:

The given word HAPPYHOLI has 9 letters

These 9 letters can e arranged in 9! ways.

But here in the given word letters H & P are repeated twice each

Therefore, Number of ways these 9 letters can be arranged is 

9!2! x 2! = 9 x 8 x 7 x 6 x 5 x 4 x 32 = 90,720 ways.

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Filed Under: Permutations and Combinations
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

7 2783
Q:

Ankita borrows Rs. 7000 at simple Interest from a lender. Atthe end of 3 years, she again borrows Rs. 3000 and settledthat amount after paying Rs. 4615 as interest after 8 years from the time she made the first borrowing. What is the rate of interest?

A) 5.5% B) 9.5%
C) 7.5% D) 6.5%
 
Answer & Explanation Answer: D) 6.5%

Explanation:

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Filed Under: Simple Interest

2 2777
Q:

Two buses travel to a place at 45 km/hr and 60 km/hr respectively. If the second bus takes 51⁄2 hours less than the first for the journey, the length of the journey is:

A) 900 km B) 940 km
C) 990 km D) 1300 km
 
Answer & Explanation Answer: C) 990 km

Explanation:
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Filed Under: Time and Distance
Exam Prep: Bank Exams

4 2773
Q:

A train travels 360 km at a uniform speed. If the speed had been 5 km/h more, it would have taken 1 hour less for the same journey. Find the speed of the train?
     

A) 42 kmph B) 43 kmph
C) 40 kmph D) 45 kmph
 
Answer & Explanation Answer: C) 40 kmph

Explanation:

We know that,  Speed = Distance/time

 

Let the speed of the train be = x kmph

           NORMAL SPEED                           SPEED 5 KMPH MORE

          Distance = 360 Km                         Distance =360
 
          speed    =  X Kmph                        Speed = (x+5)
 
            Time =360/X                              Time =360/(x+15)
          

 

For the same journey if the speed increased 10 kmph more it will take 1 hour less

 


Time with original speed - time with increased speed = 1

 => (360/x) - (360/x+10) =  1                               

 =>  (360(x+5)-360x)/x(x+5) =1

 =>   360X + 1800 -360X  = X(X+5)

  =>   X^2 + 5x - 1800 = 0

  X = 40 or -45

 X cannot be negetive value
                  

 X = 40 kmph.

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Filed Under: Problems on Trains
Exam Prep: TOEFL , GRE , GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

4 2771
Q:

2% of a = b, then b% of 10 is the same as:

A) 200% of a B) 20% of a/100
C) 20% of a/10 D) 200% of a/10
 
Answer & Explanation Answer: C) 20% of a/10

Explanation:
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Filed Under: Percentage
Exam Prep: Bank Exams

10 2771
Q:

If the price of kerosene be raised by 11%, find by how much percent a house holder must reduce his consumption of kerosene so as not to increase his expenditure?

A) 11% B) 9.09%
C) 11.09% D) 8.25%
 
Answer & Explanation Answer: B) 9.09%

Explanation:

Let the price of kerosene be x and household
consumption be y.
Expenditure = xy
New cost of kerosene = 1.1x, let new household
consumption be z.
In order to not to increase expenditure,
xy = 1.1x * a
⇒ a= 10y/ 11
⇒ consumption should decrease by = 1/11 X 100 = 9.09%

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Filed Under: Percentage
Exam Prep: Bank Exams

2 2768