Quantitative Aptitude - Arithmetic Ability Questions

C.P of article = 6500 * (100/80) = Rs. 8125 S.P for a gain of 20% = (8125*120)/100 = Rs. 9750

Let the required two numbers be a, b

From the given data,

2a + 3b = 36 .....(1)

3a + 2b = 39 .....(2)

Now, by solving 1 and 2 eqnts, we get

5a = 45

a = 9 ....(3)

Put (3) in (1), we get

2(9) + 3b = 36

=> 18 + 3b = 36

3b = 36 - 18

=> b = 18/3 = 6

Required, difference between the numbers = a + b = 9 + 6 = 15.

5/8 is Nothing but to divide 5 into 8 parts.

As 5 is smaller than 8, the quotient starts with a decimal point to make 5 as 50 to be divisible by 8. (0.)

Now 50 goes for 6 times in 8 leaving a remainder 2. (0.6)

Again 2 is smaller than 8, As it already has decimal point in the quotient, now 2 becomes 20.

Now 20 goes for 2 times in 8 leaving a remainder 4. (0.62)

Again 4 is smaller than 8, As it already has decimal point in the quotient, now 4 becomes 40.

Now 40 goes for 5 times in 8 leaving a remainder 0. (0.625)

Therefore, the decimal value of 58 is 0.625.

Now find a decimal value of 1117 and Discuss your at Discuss.

The Multiples of 4 are 4, 8, 12, 16, 20, 24, 28, 32, 36, 40 upto 40. Mutiples of 4 means which can be divided by 4 leaving remainder '0'.

Common Multiples of 4 & 6 are 12, 24, 36, 48, 60 upto 60.

Answer : 1152

Total positions are 8.

In that boys can be arranged in 4 places and girls can be arranged in 4 places and hence this can be done in 2 ways.

i.e => 4! x 4! x 2 = 24 x 24 x 2=1152.

Principle amount = Rs. 29000

Interest = Rs. 10440

Let rate of interest = r%

=> So, time = r years

According to the question,

10440 = 29000 x r x r/100

290 x r x r = 10440

r x r = 1044/29 = 36

r = 6

Hence, the rate of interest = 6% and time = 6 yrs.