6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A fraction is greater than twice its reciprocal by 7/15. What is the fraction?

A) 3/5	B) 5/3
C) 3/4	D) 4/3

Answer & Explanation Answer: B) 5/3

Explanation:

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Filed Under: Decimal Fractions
Exam Prep: Bank Exams

6 2307

Q:

If (1/cos θ) – (1/cot θ) = 1/P, then what is the value of cos θ?

A) (P + 1)/(P – 1)	B) (P2+ 1)/2P
C) 2(P2+ 1)/P	D) 2P/(P2+ 1)

Answer & Explanation Answer: D) 2P/(P2+ 1)

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Filed Under: Simplification
Exam Prep: Bank Exams

1 2306

Q:

The zeros of the cubic polynomial $2 x^{3} - x^{2} - 2 x + 1$ are a, b and c respectively. Find a+b+c :

A) -1	B) 2
C) 1	D) none

Answer & Explanation Answer: D) none

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Filed Under: Simplification
Exam Prep: AIEEE , Bank Exams , CAT

0 2305

Q:

Ravi invested Rs.P in a scheme A offering simple interest at 10% p.a. for two years. He invested the whole amount he received from scheme A, in another scheme (B) offering simple interest at 12% p.a. for five years. If the difference between the interests earned from schemes A and B was Rs. 13,00/, what is the value of P ?

A) 2500	B) 2000
C) 3000	D) 3500

Answer & Explanation Answer: A) 2500

Explanation:

It is given that the initial amount invested in scheme A is Rs P at 10%per Annum S.I. =PTR/100 = P x 10 x 2/100 Now the total amount after 2 years is = 1.2P New Rate of interest = 12% per annum Time = 5 years S.I for next 5 years when new principal amount is 1.2 P = 1.2Px12x5/100 = 0.72P Total amount after 5 years at 12% per annun = 1.72P Given that 1.72P - 1.2P = 1300 P = 1300/0.52 P = Rs. 2500

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Filed Under: Simple Interest

2 2303

Q:

The average of 41 consecutive odd numbers is 49. What is the largest number.

A) 89	B) 91
C) 93	D) 95

Answer & Explanation Answer: A) 89

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Filed Under: Average
Exam Prep: Bank Exams

1 2302

Q:

U and V started a business by investing amounts Rs 184000 and Rs 224000 respectively. If U’s share in the profit received at the end of year is Rs 20700, then what will be the total profit (in Rs)earned by them together?

A) 43200	B) 45900
C) 52300	D) 56400

Answer & Explanation Answer: B) 45900

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Filed Under: Partnership
Exam Prep: Bank Exams

0 2301

Q:

If p and q are the roots of the equation x2 –15x + r = 0 and p –q = 1, then what is the value of r ?

A) 55	B) 56
C) 60	D) 64

Answer & Explanation Answer: B) 56

Explanation:

In the below equation,

x2–15x + r = 0

sum of roots = p + q = -(-15)/1 = 15 (sum of roots for equation ax2+ bx + c is -b/a)

product of roots = pq = r/1 = r (product of roots for equation ax2+ bx + c is c/a)

given p –q = 1

also we know that p+q = 15

subtracting the squares of both

(p+q)2 + (p-q)2 = 15^2–1

p2 + q2 + 2pq –p2 –q2 +2pq = 225 -1

4pq = 224

4r = 224

r = 56

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Filed Under: Simplification
Exam Prep: Bank Exams

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Q:

If sec 300° = x, then value of x is

A) √2	B) 1/√3
C) 2	D) 1

Quantitative Aptitude - Arithmetic Ability Questions

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