Quantitative Aptitude - Arithmetic Ability Questions

Q:

In how many ways can a group of 5 men and 2 women be made out of a total of 7 men and 3 women?

A) 135 B) 63
C) 125 D) 64
 
Answer & Explanation Answer: B) 63

Explanation:

Required number of ways = (7C5*3C2) = (7C2*3C1) = 63

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Q:

If sec θ + tan θ = 2, then sec θ - tan θ = ?

 

A) 0.5 B) 1.5
C) 1 D) 0.75
 
Answer & Explanation Answer: A) 0.5

Explanation:
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0 46251
Q:

Calculate the value of x, if 1 - (x529) = (1623)

 

A) 283 B) 276
C) 273 D) 374
 
Answer & Explanation Answer: C) 273

Explanation:
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3 46146
Q:

Compute of 1848 / 231 - 10 = ?

 

A) 2 B) -2
C) 188/221 D) 1884/221
 
Answer & Explanation Answer: B) -2

Explanation:
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2 46131
Q:

Find the odd number in the given number series?

14, 27, 105, 525, 4993

A) 27 B) 105
C) 525 D) 4993
 
Answer & Explanation Answer: C) 525

Explanation:

The given number series is 14, 27, 105, 525, 4993

14

14 x 2 - 1 = 27

27 x 4 - 3 = 105

105 x 6 - 5 = 625 (not 525)

625 x 8 - 7 = 4993

 

Hence, the odd man or number in the given number series is 525.

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Filed Under: Odd Man Out
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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1 46096
Q:

Solve : x - 3 = 3x + 7

 

 

A) 5 B) -5
C) 1 D) 10/4
 
Answer & Explanation Answer: B) -5

Explanation:
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0 46088
Q:

Find the odd man out of the following series?

6, 8, 5, 10, 4, 14

A) 8 B) 10
C) 4 D) 5
 
Answer & Explanation Answer: C) 4

Explanation:

The given number series is 6, 8, 5, 10, 4, 14

6

6 + 2 = 8

8 - 3 = 5

5 + 5 = 10

10 - 7 = 3

3 + 11 = 14

...

 

Hence, the odd man in the given series is 4.

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1 46087
Q:

Three unbiased coins are tossed.What is the probability of getting at least 2 heads?

A) 1/4 B) 1/2
C) 3/4 D) 1/3
 
Answer & Explanation Answer: B) 1/2

Explanation:

Here S= {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}.

Let E = event of getting at least two heads = {THH, HTH, HHT, HHH}.

P(E) = n(E) / n(S)

      = 4/8= 1/2

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Filed Under: Probability

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