Quantitative Aptitude - Arithmetic Ability Questions

A : B : C = 500 : 300 : 200 = 5 : 3 : 2.

Let their capitals be 5x, 3x and 2x respectively.

Then, 5x = 10000  

=>  x = 2000.

C's capital = 2x = Rs. 4000.

Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.

R=100*60100*6 =10% p.a

Now, P = Rs. 12000. T = 3 years and R = 10% p.a.

C.I=Rs.12000*1+101003-1
       =Rs.3972

The year 2006 is an ordinary year. So, it has 1 odd day.

So, the day on 8th Dec, 2007 will be 1 day beyond the day on 8th Dec, 2006.

But, 8th Dec, 2007 is Saturday

S0, 8th Dec, 2006 is Friday.

Let distance = x km.
Time taken at 3 kmph : dist/speed = x/3 = 20 min late.
time taken at 4 kmph : x/4 = 30 min earlier
difference between time taken : 30-(-20) = 50 mins = 50/60 hours.
x/3- x/4 = 50/60
x/12 = 5/6
x = 10 km.

Let , S -  sample space        E - event of selecting 1 girl and 2 boys. 

Then, n(S) = Number ways of selecting 3 students out of 25 

                = 25C3 

                = 2300.

n(E) = 10C1×15C2 = 1050. 

P(E) = n(E)/n(s) = 1050/2300 = 21/46

Ans. 
17 = 2 x 6 + 5
89 = 17 x 5 + 4
359 = 89 x 4 + 3
1079 = 359 x 3 + 2
? = 1079 x 2 + 1, i.e. ? = 2159