6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Find the odd man out of the following number series?

1/2, 1, 3/2, 6, 5/2, 3

A) 1	B) 6
C) 5/2	D) 3/2

Answer & Explanation Answer: B) 6

Explanation:

The given series is 1/2, 1, 3/2, 6, 5/2, 3

1/2

1/2 + 1/2 = 1

1 + 1/2 = 3/2

3/2 + 1/2 = 2 (Not 6)

2 + 1/2 = 5/2

5/2 + 1/2 = 3

Hence, the odd man in the given number series is 6.

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Filed Under: Odd Man Out
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

1 39375

Q:

4 men can repair a road in 7 hours. How many men are required to repair the road in 2 hours ?

A) 17 men	B) 14 men
C) 13 men	D) 16 men

Answer & Explanation Answer: B) 14 men

Explanation:

M x T / W = Constant
where, M= Men (no. of men)
T= Time taken
W= Work load
So, here we apply
M1 x T1/ W1 = M2 x T2 / W2
Given that, M1 = 4 men, T1 = 7 hours ; T2 = 2 hours, we have to find M2 =?
Note that here, W1 = W2 = 1 road, ie. equal work load.
Clearly, substituting in the above equation we get, M2 = 14 men.

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Filed Under: Time and Work
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

40 39214

Q:

The H.C.F and L.C.M of two numbers are 11 and 385 respectively. If one number lies between 75 and 125 , then that number is

A) 77	B) 88
C) 99	D) 110

Answer & Explanation Answer: A) 77

Explanation:

Product of numbers = 11 x 385 = 4235

Let the numbers be 11a and 11b . Then , 11a x 11b = 4235 => ab = 35

Now, co-primes with product 35 are (1,35) and (5,7)

So, the numbers are ( 11 x 1, 11 x 35) and (11 x 5, 11 x 7)

Since one number lies 75 and 125, the suitable pair is (55,77)

Hence , required number = 77

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Filed Under: HCF and LCM

72 39213

Q:

I forgot the last digit of a 7-digit telephone number. If 1 randomly dial the final 3 digits after correctly dialing the first four, then what is the chance of dialing the correct number?

A) 1/999	B) 1/1001
C) 1/1000	D) 4/1000

Answer & Explanation Answer: C) 1/1000

Explanation:

It is given that last three digits are randomly dialled. then each of the digit can be selected out of 10 digits in 10 ways.
Hence required probability = ${(\frac{1}{10})}^{3}$ = 1/1000

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Filed Under: Probability

28 39171

Q:

The ratio 5 : 4 expressed as a percent equals :

A) 12.5 %	B) 40 %
C) 80 %	D) 125 %

Answer & Explanation Answer: D) 125 %

Explanation:

5 : 4 = 5/4 = ( (5/4) x 100 )% = 125%.

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Filed Under: Percentage

154 39135

Q:

Two horses start trotting towards each other, one from A to B and another from B to A. They cross each other after one hour and the first horse reaches B, 5/6 hour before the second horse reaches A. If the distance between A and B is 50 km. what is the speed of the slower horse?

A) 30 km/h	B) 15 km/h
C) 25 km/h	D) 20 km/h

Answer & Explanation Answer: D) 20 km/h

Explanation:

If the speed of the faster horse be $f_{s}$ and that of slower horse be $s_{s}$ then

$f_{s} + s_{s} = \frac{50}{1} = 50$

and $\frac{50}{s_{s}} - \frac{50}{f_{s}} = \frac{5}{6}$

Now, you can go through options.

The speed of slower horse is 20km/h

Since, 20+30=50

and $\frac{50}{20} - \frac{50}{30} = \frac{5}{6}$

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Filed Under: Time and Distance

159 39074

Q:

270 candidates appeared for an examination, of which 252 passed. The pass percentage is :

A) (91 + 1/3)%	B) (93 + 1/3 )%
C) (97 + 1/3 )%	D) (98 + 1/3) %

Answer & Explanation Answer: B) (93 + 1/3 )%

Explanation:

Pass percentage =[(252/270)*100] % =280/3 % = $93 \frac{1}{3}$ 9 %

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Filed Under: Percentage

109 39057

Q:

The age of a man is 4 times of his son. Five years ago, the man was nine times old as his son was at that time. The present age of man is?

Answer

Let the son's age be x years and the father's age be 4x years

$\Rightarrow (4x-5)=9(x-5)$

5x = 40

x = 8

$\inline \therefore$ present age of the father = $\inline 4x$ = $\inline 4\times 8$ = 32 years

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Subject: Problems on Ages

204 38992

Quantitative Aptitude - Arithmetic Ability Questions

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