6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

The maximum gap between two successive leap year is?

A) 4	B) 8
C) 2	D) 1

Answer & Explanation Answer: B) 8

Explanation:

This can be illustrated with an example.

Ex: 1896 is a leap year.The next leap year comes in 1904 (1900 is not a leap year).

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Filed Under: Calendar

187 33126

Q:

A, B, C hired a car for Rs. 520 and used it for 7, 8 and 11 hours respectively. Hire charges paid by B were :

A) 150	B) 160
C) 170	D) 180

Answer & Explanation Answer: B) 160

Explanation:

A : B : C = 7 : 8 : 11.

Hire charges paid by B = Rs. (520 * 8/26) = Rs. 160.

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Filed Under: Partnership

21 33102

Q:

If 15% of x = 20% of y, then x:y is ___?

A) 4:3	B) 5:4
C) 4:5	D) 3:4

Answer & Explanation Answer: A) 4:3

Explanation:

Given 15% of x = 20% of y

=> 15x = 20y

=> x/y = 20/15

=> x : y = 4 : 3

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Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

77 32938

Q:

A can run 22.5 m while B runs 25 m. In a kilometre race B beats A by:

A) 100 m	B) 75 m
C) 25 m	D) 50m

Answer & Explanation Answer: A) 100 m

Explanation:

When B runs 25 m, A runs 45/2 m

When B runs 1000 m, A runs (45/2*1/25*1000)m = 900 m.

B beats A by 100 m.

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Filed Under: Races and Games

44 32846

Q:

The difference between the simple interest on a certain sum at the rate of 10%per annum for 2 years and compound interest which is compounded every 6 months is Rs.124.05. what is the principal sum

A) Rs.6000	B) Rs.8000
C) Rs.12000	D) none of these

Answer & Explanation Answer: B) Rs.8000

Explanation:

Compound Interest on P at 10% for 2 years when interest is compounded half-yearly

= $P {(1 + \frac{\frac{R}{2}}{100})}^{2 T} - P = P {(1 + \frac{1}{20})}^{4} - P = P {(\frac{21}{20})}^{4} - P$

Simple Interest on P at 10% for 2 years = $\frac{P R T}{100} = \frac{P \times 10 \times 2}{100} = \frac{P}{5}$

Given that difference between compound interest and simple interest = 124.05

$P * {(\frac{21}{20})}^{4} - P - \frac{P}{5} = 124.05$

=> $P [{(\frac{21}{20})}^{4} - 1 - \frac{1}{5}] = 124.05$

P=8000

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

61 32825

Q:

Find the curved surface area (in cm2) of a right circular cylinder of diameter 14 cm and height 8 cm.

A) 308	B) 352
C) 327	D) 371

Answer & Explanation Answer: B) 352

Explanation:

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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams

0 32788

Q:

A man standing at a point P is watching the top of a tower, which makes an angle of elevation of 30º with the man's eye. The man walks some distance towards the tower to watch its top and the angle of the elevation becomes 60º. What is the distance between the base of the tower and the point P?

A) Data inadequate	B) 8 units
C) 12 units	D) None of these

Answer & Explanation Answer: A) Data inadequate

Explanation:

One of AB, AD and CD must have given.

So, the data is inadequate.

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Filed Under: Height and Distance

25 32687

Q:

The ratio of efficiency of A is to C is 5:3. The ratio of number of days taken by B is to C is 2:3. A takes 6 days less than C, when A and C completes the work individually. B and C started the work and left after 2 days. The number of days taken by A to finish the remaining work is:

A) 4.5	B) 5
C) 6	D) 9 1/3

Answer & Explanation Answer: C) 6

Explanation:

A : C

Efficiency 5 : 3

No of days 3x : 5x

Given that, 5x-6 =3x => x = 3

Number of days taken by A = 9

Number of days taken by C = 15

B : C

Days 2 : 3

Therefore, Number of days taken by B = 10

Work done by B and C in initial 2 days = $2 [\frac{1}{10} + \frac{1}{15}]$ = 1/3

Quantitative Aptitude - Arithmetic Ability Questions

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