6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

If the area of a semi-circle is 1925 sq.cm, then find its radius (in cm).

A) 70	B) 31
C) 62	D) 35

Answer & Explanation Answer: D) 35

Explanation:

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Filed Under: Area
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1 26795

Q:

In the following question, select the odd word from the given alternatives.

A) Red	B) Green
C) White	D) Painting

Answer & Explanation Answer: D) Painting

Explanation:

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Filed Under: Odd Man Out
Exam Prep: Bank Exams

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Q:

The area of a circular field is 13.86 hectares. Find the cost of fencing it at the rate of Rs. 4.40 per metre.

A) 2808	B) 3808
C) 4808	D) 5808

Answer & Explanation Answer: D) 5808

Explanation:

Area = (13.86 x 10000) sq.m = 138600 sq.m

${πR}^{2} = 138600 \Rightarrow R^{2} = 138600 \times \frac{7}{22} \Rightarrow R = 210 m$

Circumference = $2 {πR}^{2} = 2 \times \frac{22}{7} \times 210 = 1320 m$

Cost of fencing = Rs. (1320 x 4.40) = Rs. 5808.

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

24 26773

Q:

The cost price of a Rs.100 stock at 4 discount, when brokerage is $\frac{1}{4}$ % is :

A) Rs.95.75	B) Rs.96
C) Rs.96.25	D) Rs.104.25

Answer & Explanation Answer: C) Rs.96.25

Explanation:

CP. = $R s . (100 - 4 + \frac{1}{4})$ = Rs.96.25

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Filed Under: Stocks and Shares

18 26766

Q:

What is the least number of squares tiles required to pave the floor of a room 15.17 m long and 9.02 m broad?

A) 814	B) 714
C) 614	D) 713

Answer & Explanation Answer: A) 814

Explanation:

Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.

Area of each tile = $(41 \times 41) c m^{2}$

Required number of tiles = $\frac{1517 \times 902}{41 \times 41}$ = 814

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

26 26735

Q:

Which among the following is different?

Super Tackle, Raider, Bowler, Defender

A) Defender	B) Super Tackle
C) Bowler	D) Raider

Answer & Explanation Answer: C) Bowler

Explanation:

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Exam Prep: Bank Exams

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Q:

In a mixture of milk and water the proportion of water by weight was 75%. If in 60 gm of mixture 15 gm water was added, what would be the percentage of water ? (Weight in gm)

A) 80%	B) 70%
C) 75%	D) 62%

Answer & Explanation Answer: A) 80%

Explanation:

Water in 60 gm mixture=60 x 75/100 = 45 gm. and Milk = 15 gm.

After adding 15 gm. of water in mixture, total water = 45 + 15 = 60 gm and weight of a mixture = 60 + 15 = 75 gm.

So % of water = 100 x 60/75 = 80%.

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Filed Under: Alligation or Mixture
Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

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Q:

What is the total length intercepted between both the axes by the line 8x+4y=40?

A) 5	B) 10
C) 15	D) 20

Quantitative Aptitude - Arithmetic Ability Questions

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