6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

The inner circumference of a circular race track, 14 m wide, is 440 m. Find radius of the outer circle

A) 44	B) 22
C) 33	D) 84

Answer & Explanation Answer: D) 84

Explanation:

Let inner radius be r metres. Then, 2 $π$ r = 440 ; r = $440 \times \frac{7}{44}$ = 70 m.

Radius of outer circle = (70 + 14) m = 84 m.

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

35 28522

Q:

In the following question, select the odd letter/letters from the given alternatives.

A) BDF	B) LNP
C) TVX	D) JLP

Answer & Explanation Answer: D) JLP

Explanation:

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Exam Prep: Bank Exams , GRE , TOEFL

0 28449

Q:

In the following question, select the odd letter/letters from the given alternatives.

A) BFJ	B) PTX
C) JNR	D) KOR

Answer & Explanation Answer: D) KOR

Explanation:

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Exam Prep: Bank Exams

0 28432

Q:

If the mean of a, b, c is M and ab + bc + ca = 0, then the mean of $\frac{a^{2} + b^{2} + c^{2}}{3}$ is :

A) M	B) 3 M^2
C) 2 (M/3)	D) M^2

Answer & Explanation Answer: B) 3 M^2

Explanation:

We have : ( a + b + c) / 3 = M or (a + b + c) = 3M.

Now. ${(a + b + c)}^{2} = {(3 M)}^{2} = 9 M^{2}$ .

$< = > a^{2} + b^{2} + c^{2} + 2 (a b + b c + c a) = 9 M^{2}$

$a^{2} + b^{2} + c^{2} = 9 M^{2}, (a b + b c + c a = 0)$

Required mean = $(\frac{a^{2} + b^{2} + c^{2}}{3}) = \frac{9 M^{2}}{3} = 3 M^{2}$ .

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Filed Under: Average
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

35 28416

Q:

Select the figure which does NOT belong to the group.

A) A	B) B
C) C	D) D

Answer & Explanation Answer: C) C

Explanation:

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Filed Under: Odd Man Out
Exam Prep: Bank Exams

1 28410

Q:

A train travelling at a speed of 75 mph enters a tunnel $3 \frac{1}{2}$ miles long. The train is $\frac{1}{4}$ mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?

A) 2.5 min	B) 3 min
C) 3.2 min	D) 3.5 min

Answer & Explanation Answer: B) 3 min

Explanation:

Total distance covered = $(\frac{7}{2} + \frac{1}{4})$ miles = $\frac{15}{4}$ miles

Time taken = $(\frac{15}{4 * 75})$ hrs = $\frac{1}{20}$ hrs = $(\frac{1}{20} * 60) m i n$ = 3 min

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36 28400

Q:

A large field of 700 hectares is divided into two parts. The difference of the areas of the two parts is one-fifth of the average of the two areas. What is the area of the smaller part in hectares?

A) 315	B) 385
C) 415	D) 485

Answer & Explanation Answer: A) 315

Explanation:

Let the areas of the two parts be x and (700-x) hectares

therefore, $[x - (700 - x)] = \frac{1}{5} [\frac{x + (700 - x)}{2}]$

$\Rightarrow 2 x - 700 = 70$

$\Rightarrow x = 385$

So, the two parts are 385 and 315.

Hence, Area of the smaller = 315 hectares

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Filed Under: Area
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18 28392

Q:

Consider the following grouped frequency distribution:

x f

0-10 8

10-20 12

20-30 10

30-40 p

40-50 9

If the mean of the above data is 25.2, then what is the value of p?

A) 9	B) 10
C) 11	D) 12

Answer & Explanation Answer: C) 11

Explanation:

Mean = (sum of fixi/ (sum of f) = (8*5 + 12*15 + 10*25 + P*35 +9*45) / (8+12+10+P+9) = 25.2

Quantitative Aptitude - Arithmetic Ability Questions

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