6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?

A) Sunday	B) Saturday
C) Friday	D) Wednesday

Answer & Explanation Answer: C) Friday

Explanation:

On 31st December, 2005 it was Saturday.

Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.

therfore, on 31st December 2009, it was Thursday.

Thus, on 1st Jan, 2010 it is Friday

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Filed Under: Calendar

8 6481

Q:

In a 100 m race, A beats B by 10 m and C by 13 m. In a race of 180 m, B will beat C by

A) 5.4 m	B) 4.5 m
C) 5 m	D) 6 m

Answer & Explanation Answer: D) 6 m

Explanation:

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Filed Under: Races and Games

3 4693

Q:

In a 300 m race, A beats B by 22.5 m or 6 seconds. B's time over the course is:

A) 86 sec	B) 80 sec
C) 76 sec	D) None of these

Answer & Explanation Answer: B) 80 sec

Explanation:

B runs 45/2mts in 6 sec

B covers 300m in (6*2/45*300)sec =80 sec

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Filed Under: Races and Games

19 20181

Q:

In a 200 metres race A beats B by 35 m or 7 seconds. A's time over the course is:

A) 40 sec	B) 47 sec
C) 33 sec	D) None of these

Answer & Explanation Answer: C) 33 sec

Explanation:

B runs 35 m in 7 sec.

B covers 200 m in (7/35*200) = 40sec

B's time over the course = 40 sec.

A's time over the course (40 - 7) sec = 33 sec.

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2 3695

Q:

The compound interest on Rs. 30,000 at 7% per annum is Rs. 4347. The period (in years) is:

A) 3years	B) 2years
C) 4years	D) 6years

Answer & Explanation Answer: B) 2years

Explanation:

Amount = Rs. (30000 + 4347) = Rs. 34347.

Let the time be n years.

Then, 30000*(1+7/100)^n=34347

n= 2 years

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

0 3754

Q:

What is the difference between the compound interests on Rs. 5000 for $1 \frac{1}{2}$ years at 4% per annum compounded yearly and half-yearly?

A) Rs.3.06	B) Rs.2.04
C) Rs.3.65	D) Rs.5.40

Answer & Explanation Answer: B) Rs.2.04

Explanation:

C.I. when interest compounded yearly

$R s . [5000 * (1 + \frac{4}{100}) * (1 + \frac{\frac{1}{2} * 4}{100})]$

$R s . [5000 * \frac{26}{25} * \frac{51}{50}]$

=Rs.5034

C.I. when interest iscompounded half-yearly

$R s . [5000 * {(1 + \frac{2}{100})}^{3}]$

= Rs. 5306.04

Difference = Rs. (5306.04 - 5304) = Rs. 2.04

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

1 4669

Q:

There is 60% increase in an amount in 6 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate

A) Rs.4972	B) Rs.3972
C) Rs.5972	D) Rs.2972

Answer & Explanation Answer: B) Rs.3972

Explanation:

Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.

R= $\frac{100 * 60}{100 * 6}$ =10% p.a

Now, P = Rs. 12000. T = 3 years and R = 10% p.a.

C.I= $R s . [12000 * {[1 + \frac{10}{100}]}^{3} - 1]$
=Rs.3972

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

52 43237

Q:

The compound interest on Rs. 30,000 at 7% per annum is Rs. 4347. The period (in years) is

A) 2years	B) 3years
C) 4years	D) 5years

Answer & Explanation Answer: A) 2years

Explanation:

Amount = Rs(30000 + 4347) = Rs.34347.

Let the time be n years. Then,

$30000 {[1 + \frac{7}{100}]}^{n} = 34347$

$\Leftrightarrow$ ${(\frac{107}{100})}^{n} = \frac{34347}{30000} = \frac{11449}{10000} = {(\frac{107}{100})}^{2}$

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