Quantitative Aptitude - Arithmetic Ability Questions

Q:

The average monthly salary of 20 employees in an organisation is Rs. 1500. If the manager's salary is added, then the average salary increases by Rs. 100. What is the manager's monthly salary ?

A) 3600 B) 3700
C) 3800 D) 3900
 
Answer & Explanation Answer: A) 3600

Explanation:

Manager's monthly salary Rs. (1600 * 21 - 1500 * 20) = Rs. 3600.

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Q:

In how many ways a committee, consisting of 5 men and 6 women can be formed from 8 men and 10 women?

A) 53400 B) 17610
C) 11760 D) 45000
 
Answer & Explanation Answer: C) 11760

Explanation:

Required number of ways = 8C5*10C6 =  8C3*10C4 = 11760

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25 25947
Q:

In the following question, select the odd word pair from the given alternatives.

 

A) Kharif – Maize B) Rabi – Mustard
C) Barley – Rabi D) Kharif – Soybean
 
Answer & Explanation Answer: C) Barley – Rabi

Explanation:
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Filed Under: Odd Man Out
Exam Prep: Bank Exams

0 25909
Q:

If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days what is time taken by 15 men and 20 boys?

A) 4 days B) 6 days
C) 7 days D) 5 days
 
Answer & Explanation Answer: A) 4 days

Explanation:

Given that 

6 men and 8 boys can do a piece of work in 10 days 

26 men and 48 boys can do the same in 2 days

 

As the work done is equal,

10(6M + 8B) = 2(26M + 48B)

60M + 80B = 52M + 96B

=> M = 2B

=> B = M/2 ……(1)

 

Now Put (1) in 15M + 20B

=> 15M + 10M = 25M

Now, 6M + 8B in 10 days

=> (6M + 4M) 10 = 100M

Then D(25M) = 100M

=> D = 4 days.

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Filed Under: Time and Work
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

33 25907
Q:

A jar was full with honey. A person  used to draw out 20% of the honey from the jar and replaced it with sugar solution. He has repeated  the same process 4 times and thus there was only 512 gm of honey left in the jar, the rest part of the jar was filled with the sugar  solution. The initial amount of honey in the jar was filled with the sugar solution. The initial amount of honey in the jar was:

A) 1.25 kg B) 1 kg
C) 1.5 kg D) None of these
 
Answer & Explanation Answer: A) 1.25 kg

Explanation:

Let the initial amount of honey in the jar was K, then 

 512=K1-154     20% =20100=15

        or      

512=K454

Therefore, K = 1250

Hence initially the honey in the jar= 1.25 kg

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Filed Under: Alligation or Mixture

32 25902
Q:

A bag contains 600 coins of 25 p denomination and 1200 coins of 50 p denomination. If 12% of 25 p coins and 24% of 50 p coins are removed, the percentage of money removed from the bag is nearly :

A) 21.6 % B) 15.3 %
C) 14.6 % D) 12.5 %
 
Answer & Explanation Answer: A) 21.6 %

Explanation:

Total money = Rs.[600*(25/100)+1200*(50/100)]= Rs. 750.

 

25 paise coins removed = Rs. (600*12/100) = 72.

 

50 paise coins removed = Rs. (1200*24/100)= 288.

 

Money removed =Rs.(72*25/100+288*50/100)  = Rs.162.

 

Required percentage = (162/750*100)% = 21.6 %.

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Filed Under: Percentage

57 25852
Q:

Select the figure which does not belong to the group.

 

 

A) 4 B) 1
C) 3 D) 2
 
Answer & Explanation Answer: A) 4

Explanation:
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Filed Under: Odd Man Out
Exam Prep: Bank Exams

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Q:

The mean temperature of Monday to Wednesday was 37C and of Tuesday to Thursday was 34C . If the temperature on Thursday was (4/5) th that of Monday, the temperature on Thursday was?

Answer

\inline \fn_jvn M+T+W =(37\times 3)^{0}=111^{0}C   -----------(1)


\inline \fn_jvn T+W+Th=(34\times 3)^{0}=102^{0}C


\inline \fn_jvn \Rightarrow T+W+\frac{4}{5}M = 102^{0}C                --------------(2)


(1) - (2) gives


\inline \fn_jvn \frac{1}{5} th of temperature on Monday = 


\inline \fn_jvn \Rightarrow Temperature on Monday = \inline \fn_jvn 45^{0}C


\inline \fn_jvn \therefore Temperature on Thursday = \inline \fn_jvn \frac{4}{5}\times 45^{0}=36^{0}

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Subject: Average

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