Quantitative Aptitude - Arithmetic Ability Questions

Let the capacity of the pot be 'P' litres.
Quantity of milk in the mixture before adding milk = 4/9 (P - 8)
After adding milk, quantity of milk in the mixture = 6/11 P.
6P/11 - 8 = 4/9(P - 8)
10P = 792 - 352 => P = 44.

The capacity of the pot is 44 liters.

Let,   B1 : B2 : B3 = 3x : 4x : 5x 

again  B1 : B2 : B3 = 5y : 4y : 3y

Since there is increase in no.of oranges in first two baskets only, it means the no. of oranges remains constant in the third basket

Therefore,   5x = 3y

Hence    3x : 4x : 5x   =>   9y5:12y5:15y5 = 9y:12y:15y

and       5y : 4y : 3y   =>   25x : 20x : 15x

Therfore, increment in first basket = 16

Increment in second basket = 8

Thus, required ratio = 16/8 = 2:1

Let each side of the square be a. Then, area = .a2
New side =125a100=5a4. New area = 5a42 = 25a216

Increase in area = 25a216-a2=9a216
Increase% = 9a216*1a2*100 % = 56.25%.

Time taken in walking both ways = 7 hours 45 minutes                     --------(i)

Time taken in walking one way and riding back= 6 hours 15 minutes-------(ii)

By equation (ii)*2 -(i), we have

Time taken to man ride both ways, = 12 hours 30 minutes - 7 hours 45 minutes

                                                        = 4 hours 45 minutes

A can do the work = 18 days
B can do the work = 18/2 = 9 days
(A + B)'s 1 day work = 1/18 + 1/9 = 1/6
=> In 3 days = 3x1/6 = 1/2 work is completed.

Let the sum be Rs. x. Then,

 C.I=x*50300*1003-x=343x216-x=127x216 

⇔127x216=1270 

x=2160 

Thus, the sum is Rs. 2160

 S.I=Rs.2160*503*3*1100=Rs 1080