Quantitative Aptitude - Arithmetic Ability Questions

Q:

The base of a parallelogram is twice its height. If the area of the parallelogram is 72 sq. cm, find its height

A) 6 B) 7
C) 8 D) 9
 
Answer & Explanation Answer: A) 6

Explanation:

Let the height of the parallelogram be x. cm. Then, base = (2x) cm.

2x×x=72=>2x2=72=>x=6 

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

32 23073
Q:

Find the length of the longest pole that can be placed in a room 12 m long 8m broad and 9m high.

A) 14m B) 15m
C) 16m D) 17m
 
Answer & Explanation Answer: D) 17m

Explanation:

Length of longest pole = Length of the diagonal of the room

 

122+82+92=289 = 17m

 

 

 

 

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35 23062
Q:

Which of the following statement is correct about a triangle?

 

A) If the triangles are congruent then their area will be equal B) If the areas of two similar triangles are equal then the triangle is congruent
C) Two congruent triangles are always similar to each other D) All options are correct
 
Answer & Explanation Answer: D) All options are correct

Explanation:
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Filed Under: Area
Exam Prep: Bank Exams

0 23049
Q:

The total surface area of a cube is 253.5 sq.cm. Find its side (in cm).

 

A) 7.5 B) 5.5
C) 6.5 D) 8.5
 
Answer & Explanation Answer: C) 6.5

Explanation:
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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams

0 23046
Q:

There are 7 non-collinear points. How many triangles can be drawn by joining these points?

A) 10 B) 30
C) 35 D) 60
 
Answer & Explanation Answer: C) 35

Explanation:

A triangle is formed by joining any three non-collinear points in pairs.

 

There are 7 non-collinear points

 

The number of triangles formed = 7C3 = 35

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15 23045
Q:

How many arrangements of the letters of the word ‘BENGALI’ can be made if the vowels are to occupy only odd places.

A) 720 B) 576
C) 567 D) 625
 
Answer & Explanation Answer: B) 576

Explanation:

There are 7 letters in the word Bengali of these 3 are vowels and 4 consonants.

 

There are 4 odd places and 3 even places. 3 vowels can occupy 4 odd places in 4P3 ways and 4 constants can be arranged in 4P4 ways.

 

Number of words =4P3  x 4P4= 24 x 24 = 576

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18 23036
Q:

A train moves with a speed of 108 kmph. Its speed in metres per second is :

A) 10.8 B) 18
C) 30 D) 38.8
 
Answer & Explanation Answer: C) 30

Explanation:

108 kmph = 108*[5/18] m/sec = 30 m / s.

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Filed Under: Problems on Trains

42 23001
Q:

What was the day of the week on 16th August, 1947?

A) Sunday B) Monday
C) Saturday D) Thursday
 
Answer & Explanation Answer: C) Saturday

Explanation:

15th August, 1947 = (1946 years + Period from 1st Jan., 1947 to 15th )

 

Counting of odd days:

 1600 years have 0 odd day. 300 years have 1 odd day.

 

 47 years = (11 leap years + 36 ordinary years)= [(11 x 2) + (36 x 1) ]odd days = 58 odd days = 2 odd days.

 

Jan  Feb  Mar  Apr  May  Jun  Jul  Aug.

31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 227 days = (32 weeks + 3 days) = 3,

 

Total number of odd days = (0 + 1 + 2 + 3) odd days = 6 odd days.

 

Hence, the required day was 'Saturday'.

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Filed Under: Calendar

86 22996