6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A sweet seller sells 3/5th part of sweets at a profit of 10% and remaining at a loss of 5%. If the total profit is Rs 1500, then what is the total cost price of sweets ?

A) Rs.37,500	B) Rs.36,400
C) Rs.37,415	D) Rs.36,500

Answer & Explanation Answer: A) Rs.37,500

Explanation:

Assume A be the cost price.

Therefore,
$(\frac{3}{5} \times A \times \frac{10}{100}) - (\frac{2}{5} \times A \times \frac{5}{100}) = 1500$

=> A = Rs 37,500.

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Filed Under: Profit and Loss
Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

30 20650

Q:

The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:

A) 1677	B) 1683
C) 2523	D) 3363

Answer & Explanation Answer: B) 1683

Explanation:

L.C.M. of 5, 6, 7, 8 = 840.

Required number is of the form 840k + 3

Least value of k for which (840k + 3) is divisible by 9 is k = 2.

Required number = (840 x 2 + 3) = 1683.

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Filed Under: HCF and LCM

25 20649

Q:

If 18 bindres bind 900 books in 10 days , How many binders will be required to bind 660 books in 12 days?

A) 22	B) 14
C) 13	D) 11

Answer & Explanation Answer: D) 11

Explanation:

Let the required no of binders be X.

Less books , Less binders (Direct Proportion)

More days, Less binders (Indirect proportion)

$\begin{array}{r} \begin{matrix} B o o k s & 900 : 660 \end{matrix} \\ \begin{matrix} D a y s & 12 : 10 \end{matrix} \end{array}\} ⋮ ⋮ 18 : x$

Therefore, (900 * 12 * x) = (660 * 10 * 18)

=> x = 11

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Filed Under: Chain Rule

38 20634

Q:

The difference between simple interest and compound interest on Rs. 1200 for one year at 10% per annum reckoned half yearly is

A) Rs.2.50	B) Rs.3
C) Rs.4	D) Rs.4.50

Answer & Explanation Answer: B) Rs.3

Explanation:

S.I

= Rs.(1200x10x1/100)

= Rs.120.

C.I

= Rs[(1200x1+5/100)² -1200]

= Rs.123.

Difference

= Rs.[123-120]

= Rs. 3.

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Filed Under: Compound Interest
Exam Prep: GRE

29 20632

Q:

If 6 years are subtracted from the present age of Arun and the remainder is divided by 18, then the present age of his grandson Gokul is obtained. If Gokul is 2 years younger to Madan whose age is 5 years, then what is the age of Arun ?

A) 72 years	B) 54 years
C) 60 years	D) 47 years

Answer & Explanation Answer: C) 60 years

Explanation:

Let the Present age of arun is x
Gokul's age = 5-2 = 3
x-6/18 = 3
x-6 = 54
x = 60
Arun's present age = 60 years

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Filed Under: Problems on Ages
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

22 20623

Q:

A room 5m 55cm long and 3m 74cm broad is to be paved with square tiles.Find the least number of square tiles required to cover the floor?

A) 156	B) 166
C) 176	D) 186

Answer & Explanation Answer: C) 176

Explanation:

Area of the room=(544 * 374)

size of largest square tile= H.C.F of 544 & 374 = 34 cm

Area of 1 tile = (34 x 34) $c m^{2}$

Number of tiles required== [(544 x 374) / (34 x 34)] = 176

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

54 20594

Q:

A large cube is formed from the material obtained by melting three smaller cubes of 3, 4 and 5 cm side. What is the ratio of the total surface areas of the smaller cubes and the large cube?

A) 2 : 1	B) 3 : 2
C) 25 : 18	D) 27 : 20

Answer & Explanation Answer: C) 25 : 18

Explanation:

Volume of the large cube = $(3^{3} + 4^{3} + 5^{3})$ = 216 cu.cm.

Let the edge of the large cube be a.

So, $a^{3}$ = 216

=>a = 6 cm.

Required ratio = $\frac{6 (3^{2} + 4^{2} + 5^{2})}{6 (6^{2})} = \frac{25}{18}$

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Filed Under: Volume and Surface Area

18 20588

Q:

Find the total surface area (in cm2) of a right circular cylinder of diameter 7 cm and height 6 cm.

A) 187	B) 209
C) 163	D) 149

Quantitative Aptitude - Arithmetic Ability Questions

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