6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A can give B 100 meters start and C 200 meters start in a kilometer race. How much start can B give C in a kilometer race?

A) 110.12 meters	B) 111.12 meters
C) 112.12 meters	D) 113.12 meters

Answer & Explanation Answer: B) 111.12 meters

Explanation:

A runs 1000 meters while B runs 900 meters and C runs 800 meters.

Therefore, B runs 900 meters while C runs 800 meters.

So, the number of meters that C runs when B runs 1000 meters = (1000 x 800)/900 = 8000/9 = 888.88 meters

Thus, B can give C (1000 - 888.88) = 111.12 meters start

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Filed Under: Races and Games

22 20937

Q:

5 men and 4 women are to be seated in a row so that the women occupy the even places . How many such arrangements are possible?

A) 2880	B) 1440
C) 720	D) 2020

Answer & Explanation Answer: A) 2880

Explanation:

There are total 9 places out of which 4 are even and rest 5 places are odd.

4 women can be arranged at 4 even places in 4! ways.

and 5 men can be placed in remaining 5 places in 5! ways.

Hence, the required number of permutations = 4! x 5! = 24 x 120 = 2880

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Filed Under: Permutations and Combinations
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

8 20927

Q:

A large cube is formed from the material obtained by melting three smaller cubes of 3, 4 and 5 cm side. What is the ratio of the total surface areas of the smaller cubes and the large cube?

A) 2 : 1	B) 3 : 2
C) 25 : 18	D) 27 : 20

Answer & Explanation Answer: C) 25 : 18

Explanation:

Volume of the large cube = $(3^{3} + 4^{3} + 5^{3})$ = 216 cu.cm.

Let the edge of the large cube be a.

So, $a^{3}$ = 216

=>a = 6 cm.

Required ratio = $\frac{6 (3^{2} + 4^{2} + 5^{2})}{6 (6^{2})} = \frac{25}{18}$

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Filed Under: Volume and Surface Area

18 20919

Q:

If 18 bindres bind 900 books in 10 days , How many binders will be required to bind 660 books in 12 days?

A) 22	B) 14
C) 13	D) 11

Answer & Explanation Answer: D) 11

Explanation:

Let the required no of binders be X.

Less books , Less binders (Direct Proportion)

More days, Less binders (Indirect proportion)

$\begin{array}{r} \begin{matrix} B o o k s & 900 : 660 \end{matrix} \\ \begin{matrix} D a y s & 12 : 10 \end{matrix} \end{array}\} ⋮ ⋮ 18 : x$

Therefore, (900 * 12 * x) = (660 * 10 * 18)

=> x = 11

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Filed Under: Chain Rule

38 20884

Q:

∆PQR is right angled at Q. If m∠P = 60 deg, then find the value of (secR + 1/2).

A) (2√2+√3)/2	B) (√3+4)/2√3
C) √3+2	D) 5/6

Answer & Explanation Answer: B) (√3+4)/2√3

Explanation:

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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams

0 20872

Q:

A room 5m 55cm long and 3m 74cm broad is to be paved with square tiles.Find the least number of square tiles required to cover the floor?

A) 156	B) 166
C) 176	D) 186

Answer & Explanation Answer: C) 176

Explanation:

Area of the room=(544 * 374)

size of largest square tile= H.C.F of 544 & 374 = 34 cm

Area of 1 tile = (34 x 34) $c m^{2}$

Number of tiles required== [(544 x 374) / (34 x 34)] = 176

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

54 20844

Q:

The difference between Simple Interest and True Discount on a certain sum of money for 6 months at $12 \frac{1}{2}$ % per annum is Rs 25. Find the sum.

A) Rs.6800	B) Rs.6500
C) Rs.6000	D) Rs.6200

Answer & Explanation Answer: A) Rs.6800

Explanation:

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Filed Under: True Discount

53 20842

Q:

The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:

A) 1677	B) 1683
C) 2523	D) 3363

Answer & Explanation Answer: B) 1683

Explanation:

L.C.M. of 5, 6, 7, 8 = 840.

Required number is of the form 840k + 3

Least value of k for which (840k + 3) is divisible by 9 is k = 2.

Required number = (840 x 2 + 3) = 1683.

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Filed Under: HCF and LCM

25 20827

Quantitative Aptitude - Arithmetic Ability Questions

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