6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Find the odd word/letters/number from the given alternatives.

(A) BCE (B) WXZ (C) MNP (D) GHK

A) A	B) B
C) C	D) D

Answer & Explanation Answer: D) D

Explanation:

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams

0 19234

Q:

For any two numbers m , n ; (m+n) : (m-n) : mn = 7: 1: 60 . Find the value of 1/m : 1/n

A) 4:3	B) 8:7
C) 3:4	D) 7:8

Answer & Explanation Answer: C) 3:4

Explanation:

$\frac{m + n}{m - n} = \frac{7 x}{x} \Rightarrow \frac{m}{n} = \frac{4 x}{3 x}$

Again $m n = 12 x^{2}$

and mn =60x

so, $60 x = 12 x^{2} \Rightarrow x = 5$

=> m= 20 and n= 15

Hence, $\frac{1}{m} : \frac{1}{n} = \frac{1}{20} : \frac{1}{15} = 3 : 4$

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Filed Under: Ratios and Proportions

47 19211

Q:

If a number 6573547x45 is divisible by 9, then find the value of x.

A) 7	B) 0
C) 8	D) 6

Answer & Explanation Answer: C) 8

Explanation:

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Filed Under: Problems on Numbers
Exam Prep: Bank Exams

1 19210

Q:

Find the volume (in cm3) of a hemisphere of diameter 7 cm.

A) 77	B) 63
C) 89.83	D) 54.13

Answer & Explanation Answer: C) 89.83

Explanation:

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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams

0 19195

Q:

Eight years ago, Ajay's age was 4/3 times that of Vijay. Eight years hence, Ajay's age will be 6/5 times that of Vijay. What is the present age of Ajay ?

A) 41 yrs	B) 40 yrs
C) 37 yrs	D) 33 yrs

Answer & Explanation Answer: B) 40 yrs

Explanation:

Let the present ages of Ajay and Vijay be 'A' and 'V' years respectively.

=> A - 8 = 4/3 (V - 8) and A + 8 = 6/5 (V + 8)

=> 3/4(A - 8) = V - 8 and 5/6(A + 8) = V + 8

V = 3/4 (A - 8) + 8 = 5/6 (A + 8) - 8

=> 3/4 A - 6 + 8 = 5/6 A + 20/3 - 8

=> 10 - 20/3 = 10/12 A - 9/12 A

=> 10/3 = A/12 => A = 40.

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Filed Under: Problems on Ages
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

26 19118

Q:

A child has three different kinds of chocolates costing Rs.2, Rs.5, Rs.10. He spends total Rs. 120 on the chocolates. what is the minimum possible number of chocolates he can buy, if there must be atleast one chocolate of each kind?

A) 22	B) 19
C) 17	D) 15

Answer & Explanation Answer: C) 17

Explanation:

Minimum number of chocolates are possible when he purchases maximum number of costliest chocolates.

Thus, 2 x 5 + 5 x 2 =Rs.20

Now Rs.100 must be spend on 10 chocolates as 100 = 10 x 10.

Thus minumum number of chocolates = 5 + 2 + 10 = 17

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Filed Under: Ratios and Proportions

48 19114

Q:

Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is :

A) 12	B) 137
C) 14	D) 15

Answer & Explanation Answer: D) 15

Explanation:

Let the three integers be x, x + 2 and x + 4. Then, 3x = 2 (x + 4) + 3 <=> x = 11.

Third integer = x + 4 = 15.

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Filed Under: Problems on Numbers

38 19075

Q:

3 x 0.3 x 0.03 x 0.003 x 30 =?

A) 0.0000243	B) 0.000243
C) 0.00243	D) 0.0243

Quantitative Aptitude - Arithmetic Ability Questions

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