6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Find the appropriate relation for quantity 1 and quantity 2 in the following question:

Quantity I: the unit digit in (6817)754

Quantity II: the unit digit in (365×659×771)

A) Quantity I > Quantity II	B) Quantity I < Quantity II
C) Quantity I ≥ Quantity II	D) Quantity I ≤ Quantity II

Answer & Explanation Answer: A) Quantity I > Quantity II

Explanation:

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams , GATE
Job Role: Bank Clerk , Bank PO

1 18588

Q:

What value should come in place of the question mark (?) in the following question?

$1637 + 1832 = 45^{2} + {(?)}^{2}$

A) 38	B) 42
C) 46	D) 54

Answer & Explanation Answer: A) 38

Explanation:

3469 = 2025+?x?
? x ?= 3469-2025
? x ?= 1444
? = 38

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams , GATE

0 18563

Q:

A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train ?

A) 69.5 km/hr	B) 70 km/hr
C) 79 km/hr	D) 79.2 km/hr

Answer & Explanation Answer: D) 79.2 km/hr

Explanation:

Let the length of the train be x metres and its speed by y m/sec.

Then, x/y = 8 => x = 8y

Now, (x+264)/20 = y
$\Rightarrow$ 8y + 264 = 20y
$\Rightarrow$ y = 22.
$\therefore$ Speed = 22 m/sec = (22*18/5) km/hr = 79.2 km/hr.

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Filed Under: Problems on Trains

60 18522

Q:

The denominator of a fraction is 3 more than the numerator. If the numerator as well as the denominator is increased by 4, the fraction becomes 4/5. What was the original fraction ?

A) 7/11	B) 8/11
C) 9/11	D) 10/11

Answer & Explanation Answer: B) 8/11

Explanation:

Let the numerator be x Then, denominator = x + 3.

Now. (x + 4)/(x + 3) +4 = 4/5 <=> 5 (x + 4) = 4(x + 7)

=> x = 8.

The fraction is 8/11.

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Filed Under: Problems on Numbers

24 18501

Q:

If the C.I. on a sum for 2 years at 12 1/2 % per annum is Rs. 510, the S.I. on the same sum at the same rate for the same period of time is ?

A) Rs. 580	B) Rs. 480
C) Rs. 550	D) Rs. 470

Answer & Explanation Answer: B) Rs. 480

Explanation:

Let the sum be Rs. P. Then,

$[P {(1 + \frac{25}{2 x 100})}^{2} - P]$ = 510

P[ ${(\frac{9}{8})}^{2}$ - 1] = 510.

Sum = Rs. 1920

So, S.I. = (1920 x 25 x 2) / (2 x 100) = Rs. 480

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Filed Under: Simple Interest
Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

39 18496

Q:

What value should come in place of the question mark (?) in the following question?

$325 - 12^{2} + 75 = ?^{2} - 68$

A) 18	B) 324
C) 18	D) 3242

Answer & Explanation Answer: C) 18

Explanation:

$?^{2}$ = 325 – 144 + 75 + 68
= 468 – 144 = 324
(?) = 18,-18

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams , GATE

0 18488

Q:

A contractor undertakes to complete a work in 130 days. He employs 150 men for 25 days and they complete 1/4 of the work . He then reduces the number of men to 100, who work for 60 days, after which there are 10 days holidays.How many men must be employed for the remaining period to finish the work?

Answer

150 men in 25 days do = $\frac{1}{4}$ work

Let 1 man in 1 day does = x work

Total work done by 150 men in 25 days = 150x * 25 = $\frac{1}{4}$ work => x = $\frac{1}{15000}$

Therefore, 100 men in 60 days do = 100 * 60x = 6000x work = 6/15 = 2/5

Total work done = $\frac{1}{4} + \frac{2}{5} = \frac{13}{20}$

Therefore, Remaining work = 1 - $\frac{13}{20}$ = $\frac{7}{20}$

Remaining time = 130 - (25+60+10) = 35 days

Therefore, work is done in 25 days by 150 men.

Therefore, Work is done in 35 days by 150 men.

Hence, he should employ 50 more men.

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Subject: Time and Work Exam Prep: Bank Exams , AIEEE
Job Role: Bank PO

47 18480

Q:

At what time, in minutes, between 3 o'clock and 4 o'clock, both the needles will coincide each other?

A. $5 \frac{1}{11}$

B. $15 \frac{4}{15}$

C. $16 \frac{4}{11}$

D. $4 \frac{4}{15}$

A) Option A	B) Option B
C) Option C	D) Option D

Answer & Explanation Answer: C) Option C

Explanation:

At 3 o'clock, the minute hand is 15 min. spaces apart from the hour hand.

To be coincident, it must gain 15 min. spaces.

55 min. are gained in 60 min.

Then 15 min spaces are gained in = $\frac{60}{55} \times 15$ min.

Therefore, The hands are coincident at $16 \frac{4}{11}$ min. past 3 o'clock.

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Filed Under: Clocks
Exam Prep: Bank Exams
Job Role: Bank Clerk

18 18463

Quantitative Aptitude - Arithmetic Ability Questions

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