Quantitative Aptitude - Arithmetic Ability Questions

Q:

If 47. 2506 = 4*A + 7/B + 2*C + 5/D + 6*E, then the value of 5*A + 3*B + 6*C + D + 3*E is :

A) 55.6003 B) 53.603
C) 153.6003 D) 213.003
 
Answer & Explanation Answer: C) 153.6003

Explanation:

4*A + 7/B + 2*C + 5/D + 6*E =47.2506
=> 4 * A + 7/B + 2 *C + 5/D + 6*E = 40 + 7 + 0.2 + 0.05 + 0.0006
Comparing the terms on both sides, we get :
4*A =40, 7/B = 7, 2*C = 0.2, 5/D = 0.05, 6*E = 0.0006
A = 10,
B = 1,
C = 0.1,
D = 100,
E = 0.0001.
5*A + 3*B + 6*C + D + 3*E =(5*10) + (3*1) + (6*0.1) +100 +(3*0.0001)
=50 + 3 + 0.6 + 100 + 0.003 = 153.6003.

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Filed Under: Decimal Fractions

60 17186
Q:

The true discount on a bill of Rs. 2160 is Rs. 360. What is the banker's discount?

A) Rs. 432 B) Rs. 422
C) Rs. 412 D) Rs. 442
 
Answer & Explanation Answer: A) Rs. 432

Explanation:

F = Rs. 2160

TD = Rs. 360

PW = F - TD = 2160 - 360 = Rs. 1800

True Discount is the Simple Interest on the present value for unexpired time

=>Simple Interest on Rs. 1800 for unexpired time = Rs. 360

Banker's Discount is the Simple Interest on the face value of the bill for unexpired time

= Simple Interest on Rs. 2160 for unexpired time

=(360/1800)* 2160

= (1/5) * 2160

=Rs. 432

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Filed Under: Banker's Discount

3 17163
Q:

1595 is the sum of the square of three consecutive odd numbers. Find the numbers.

 

A) 19, 21, 23 B) 17, 19, 21
C) 21, 23, 25 D) 23, 25, 27
 
Answer & Explanation Answer: C) 21, 23, 25

Explanation:
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Filed Under: Problems on Numbers
Exam Prep: Bank Exams

3 17149
Q:

A train overtakes two girls who are walking in the  opposite direction in which the train  is going at the rate of 3 km/h and 6km/h and passes them completely in 36 seconds and 30 seconds respectively. The length of the train is:

A) 120m B) 150m
C) 125m D) None of these
 
Answer & Explanation Answer: B) 150m

Explanation:

Let the length of the train e x meter, and let the speed of train be y km/h, then

x=y+3×518×36   --------(1)   and   

x=y+6×518×30  ---------(2)

  

From eq (1) and (2), we get      

y = 12 km/h

Therefore,  x=(y+3)×518×36   =>  x= 150 m

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Filed Under: Time and Distance

35 17114
Q:

A is 3 times faster than B. If A can finish a work 32 days less than that of B, find the number of days need to finish the work if both are working together?

A) 12 days B) 24 days
C) 32 days D) 16 days
 
Answer & Explanation Answer: A) 12 days

Explanation:

It is given that efficiency ratio =3:1

so time ratio will be 1:3 (since work is same)

 

Also given that time diff = 32 days. ratio difference = 3-1 =2 

2 ratio = 32 days

1 ratio = 16 days.

So A will alone finish it in 16 days and B will finish it in 16*3 = 48 days.

 

Total work = LCM of 16 and 48 = 48.

Total time = Total work/Total efficiency 

ie; 48/4= 12 days.

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Filed Under: Time and Work
Exam Prep: Bank Exams
Job Role: Bank PO , Bank Clerk

8 17110
Q:

Six years ago Anita was P times as old as Ben was. If Anita is now 17 years old, how old is Ben now in terms of P ?

A) 11/P + 6 B) P/11 +6
C) 17 - P/6 D) 17/P
 
Answer & Explanation Answer: A) 11/P + 6

Explanation:

Let Ben’s age now be B

Anita’s age now is A.

(A - 6) = P(B - 6)

But A is 17 and therefore 11 = P(B - 6)

11/P = B-6

(11/P) + 6 = B

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Filed Under: Problems on Ages
Exam Prep: GRE

84 17108
Q:

Two cards are drawn from a pack of well shuffled cards. Find the probability that one is a club and other in King

A) 1/52 B) 1/26
C) 1/13 D) 1/2
 
Answer & Explanation Answer: B) 1/26

Explanation:

Let X be the event that cards are in a club which is not king and other is the king of club.
Let Y be the event that one is any club card and other is a non-club king.
Hence, required probability:
=P(A)+P(B)

 

=12C1*1C152C2+13C1*3C152C2

 

=12*252*51+13*3*252*5124+7852*51 = 126

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Filed Under: Probability

27 17107
Q:

Ten years ago, Kumar was thrice as old as Sailesh was but 10 years hence, he will be only twice as old. Find Kumar’s present age ?

A) 50 years B) 70 years
C) 60 years D) 40 years
 
Answer & Explanation Answer: B) 70 years

Explanation:

Let Kumar’s present age be "x" years and Sailesh’s present age be "y" years.
Then, according to the first condition,


x - 10 = 3(y - 10) => x - 3y = - 20 ........(1)

Now, Kumar’s age after 10 years = (x + 10) years.

Sailesh’s age after 10 years = (y + 10) years.

(x + 10) = 2 (y + 10)  => x - 2y = 10 ......(2)

 

Solving (1) and (2),

we get x = 70 and y = 30

Kumar’s present age = 70 years    and  Sailesh’s present age = 30 years.

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Filed Under: Problems on Ages
Exam Prep: CAT
Job Role: Bank PO

12 17051