Quantitative Aptitude - Arithmetic Ability Questions

The possible outcomes are as follows :

5H, 5T, (H, 4T), (T, 4H), (2H, 3T) (3H, 2T), i.e. 6 outcomes in all.

Therefore the probability that head appears an odd number of times = 3/6 =1/2 (In only three outcomes out of the six outcomes, head appears an odd number of times).

Let A's age 10 years ago = x years.
Then, B's age 10 years ago = 2x years.
(x + 10) / (2x+ l0) = 3/4
=> x = 5.
So, the total of their present ages =(x + 10 + 2x + 10)
= (3x + 20) = 35 years.

perimeter of window = πr+2r 

= [(22/7) x (63/2) + 63] = 99+63 = 162 cm

Let the diagonals of the squares be 2x and 5x respectively.
Ratio of their areas =  12*2x2:12*5x2=4:25

Given : S.I. = Rs. 50.

I  gives,  R = 10% p.a.

II gives,  T = 10 years.

Sum = (100 x S.I)/(t x r ) =  Rs.(100 x 50)/(10 x 10) = Rs.50

The triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.

Area of the triangle =1/2 x base x height => 1/2 x 24 x 10 = 120 sq.cm

The measure of the third side of a triangle must lie between the sum and the difference of the other two sides. Using this fact along with the answer choices, we can eliminate the wrong answers. 

• Option A  cannot be correct because 4 would not be the longest side.(sides 4, 5, and 4)   

• Option B could be correct because the other two sides would be 3 and 4.  

• Option C cannot be correct because this third side would be greater than the sum of the other two sides.