6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

12 men complete a work in 9 days. After they have worked for 6 days, 4 more men join them. How many days will they take to complete the remaining work ?

A) 2 days	B) 2.5 days
C) 2.25 days	D) 3 days

Answer & Explanation Answer: C) 2.25 days

Explanation:

1 man's 1 day work = 1/108
12 men's 6 day's work = 1/9 x 6 = 2/3

Remaining work = 1 - 2/3 = 1/3

16 men's 1 day work = 1/108 x 16 = 4/27
4/27 work is done by them in 1 day.

1/3 work is done by them in 27/4 x 1/3 = 9/4 days.

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Filed Under: Time and Work
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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18 14416

Q:

One year ago the ratio between Maneela’s and Shanthi’s salary was 3 : 4. The ratios of their individual salaries between last year’s and this year’s salaries are 4 : 5 and 2 : 3 respectively. At present the total of their salary is Rs. 4160. The salary of Maneela, now is?

A) Rs. 1600	B) Rs. 1700
C) Rs. 1800	D) Rs. 1900

Answer & Explanation Answer: A) Rs. 1600

Explanation:

Let the salaries of Maneela and Shanthi one year before be M1, S1 & now be M2, S2 respectively.

Then, from the given data,

M1/S1 = 3/4 .....(1)

M1/M2 = 4/5 .....(2)

S1/S2 = 2/3 .....(3)

and M2 + S2 = 4160 .....(4)

Solving all these eqtns, we get M2 = Rs. 1600.

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Filed Under: Ratios and Proportions
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
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47 14402

Q:

Find the present worth of Rs.930 due 3 years hence at 8% per annum.Aso find the discount?

A) 186	B) 180
C) 185	D) 189

Answer & Explanation Answer: B) 180

Explanation:

P.W = [100 x Amount] / [100+(R x T)]

=[100 x 930] / [100+(8x3)] = Rs. 750

T.D = Amount - P.W = 930 - 750 = Rs.180

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Filed Under: True Discount

21 14401

Q:

A sum is being lent at 20 % per annum compound interest.what is the ratio of increase in amount of 4th year to 5th year?

A) 4:5	B) 5:4
C) 5:6	D) can't be determined

Answer & Explanation Answer: C) 5:6

Explanation:

$\frac{P {(1 + \frac{r}{100})}^{4}}{P {(1 + \frac{r}{100})}^{5}} = \frac{1}{(1 + \frac{r}{100})} = \frac{100}{100 + r} = \frac{100}{120} = \frac{5}{6}$

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Filed Under: Compound Interest

50 14378

Q:

A train running at the speed of 40 km/hr crosses a signal pole in 9 seconds. Find the length of the train ?

A) 90 mts	B) 150 mts
C) 120 mts	D) 100 mts

Answer & Explanation Answer: D) 100 mts

Explanation:

We know that $S p e e d = \frac{d i s \tan c e}{t i m e}$

distance= speed * time

$\Rightarrow$ $d = (40 \times \frac{5}{18}) \times 9$

d= 100 mts.

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Filed Under: Problems on Trains
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11 14375

Q:

If n is natural number , then $(6 n^{2} + 6 n)$ is always divisible by :

A) 6 only	B) 6 and 12 both
C) 12 only	D) by 18 only

Answer & Explanation Answer: B) 6 and 12 both

Explanation:

$(6 n^{2} + 6 n) = 6 n (n + 1)$ , which is always divisible by 6 and 12 both, since n(n+1) is always even.

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Filed Under: Numbers

12 14336

Q:

A rectangular plot measuring 90 metres by 50 metres is to be enclosed by wire fencing. If the poles of the fence are kept 5 metres apart, how many poles will be needed?

A) 56m	B) 65m
C) 34m	D) 36m

Answer & Explanation Answer: A) 56m

Explanation:

Length of the wire fencing = perimeter = 2(90 + 50) = 280 metres

Two poles will be kept 5 metres apart. Also remember that the poles will be placed along the perimeter of the rectangular plot, not in a single straight line which is very important.

Hence number of poles required = 280 / 5 = 56

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

19 14331

Q:

A sum at simple interest at $13 \frac{1}{2}$ % per annum amounts to Rs. 2502.50 after 4 years. Find the sum

A) Rs.1625	B) Rs1525
C) Rs.1425	D) Rs.1325

Answer & Explanation Answer: A) Rs.1625

Explanation:

Let sum be Rs.x then, S.I. =Rs. [ x * (27/2) * 4 * (1/100) ] = Rs. 27x/50

Amount =Rs [ x + (27x/50)] = Rs.77x/50

=> 77X/50 = 2502.50

=>X= (2502.50 * 50)/77 = 1625

Hence Sum = Rs.1625

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Filed Under: Simple Interest
Exam Prep: GRE
Job Role: Bank PO

11 14321

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