Quantitative Aptitude - Arithmetic Ability Questions

First letter can be posted in 4 letter boxes in 4 ways. Similarly second letter can be posted in 4 letter boxes in 4 ways and so on.

Hence all the 5 letters can be posted in = 4 x 4 x 4 x 4 x 4 = 1024

Let ratio of the incomes of Pavan and Amar be 4x and 3x

and Ratio of their expenditures be 3y and 2y

4x - 3y = 1889 ......... I

and

3x - 2y = 1889 ...........II

I and II

y = 1889

and x = 1889

Pavan's income = 7556

 Let sum be Rs.x then, S.I. =Rs. [ x * (27/2) * 4 * (1/100) ] = Rs. 27x/50 

Amount =Rs [ x + (27x/50)] = Rs.77x/50 

=> 77X/50 = 2502.50  

=>X= (2502.50 * 50)/77 = 1625 

Hence Sum = Rs.1625

6n2+6n=6nn+1, which is always divisible by 6 and 12 both, since n(n+1) is always even.

We know that   Speed=distancetime 

distance= speed * time

⇒ d=40×518×9

   d= 100 mts.

Let the side of the square be x. Then, its diagonal = 2x.  

Radius of incircle = x/2  and radius of circumcircle =2x2 .

Therefore, required ratio = πx24:πx22 = 14:12=1:2

Let, Ages of Vijaya and Simran – 1 year ago was 4A and A years correspondingly.
Then, [(4A + 1) + 6] – [(A + 1) + 6] = 9
3A = 9  => A = 3

Needed Ratio = (4A + 1) : (A + 1) = 13 : 4

Let the triangle and parallelogram have common base b, 

let the Altitude of triangle is h1 and of parallelogram is h2(which is equal to 100 m), then  

Area of triangle    = 12×b×h1 

Area of rectangle  = b*h2 

As per Given,

12*b*h1=b*h2

12*b*h1=b*100

 h1=200